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3 years ago

Why can beta particles pass through materials more easily than alpha particles?

2 answers:

5 0

<span>Good Morning!

A) Beta particles are less energetic than alpha particles.
C) The beta particles are negatively charged;
D) Beta particles move much faster than alpha.
-
B) The beta particles are smaller, so it is that they pass better.

hugs!</span>

sergeinik [125]3 years ago

5 0

Answer: Option (B) is the correct answer.

Explanation:

Alpha particles are helium atoms whereas beta particles are just electrons. Electrons are much lighter than alpha particles (which include both protons and neutrons).

Therefore, electrons can move quickly from one place to other. Also, an electron or beta particle is 8,000 times smaller than alpha particle.

Hence, we can conclude that beta particles pass through materials more easily than alpha particles because beta particles are smaller.

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A brick is 32cm long and 10cm wide. It weighs 16N and is lying on the ground. Find the pressure exerted by the brick on the grou

Vaselesa [24]

Answer:

Below

Explanation:

First, we need to convert the dimension from cm to m before plugging it into the equation:

32 / 100 = 0.32 m

10 / 100 = 0.1 m

You can use this equation to find the pressure exerted on the ground

Pressure = Force / Area

Plugging our values in.....

Pressure = 16 Newtons / (0.1)(0.32)

= 16 Newtons / 0.032

= 500 N/m^2

Hope this helps! Best of luck <3

4 0

3 years ago

A corrosion cell consisting of Zinc and Nickel is formed. Which of the following statement is true? (A) Nickel will act as Anode

Yanka [14]

Answer: B) Zinc will act as Anode

Explanation:

Standard reduction potential of zinc and nickel are:

$E^0_{[Zn^{2+}/Zn]}= -0.76V$

$E^0_{[Ni^{2+}/Ni]}=-0.25V$

Here Zinc undergoes oxidation by loss of electrons, thus act as anode as it has more negative reduction potential.

Nickel undergoes reduction by gain of electrons and thus act as cathode. as it has less negative reduction potential.

$Zn+Ni^{2+}\rightarrow Zn^{2+}+Ni$

$E^0_{cell}=E^0_{cathode}- E^0_{anode}$

Where both $E^0$ are standard reduction potentials.

$E^0=E^0_{[Ni^{2+}/Ni]}- E^0_{[Zn^{2+}/Zn]}$

$E^0=0.25-(-0.76V)=0.51V$

As the emf is positive, the reaction is spontaneous and reaction will occur.

Thus Zinc will act as anode.

4 0

4 years ago

A ski jumper travels down a slope and leaves

Serhud [2]

Question seems to be missing. Found it on google:

a) How long is the ski jumper airborne?

b) Where does the ski jumper land on the incline?

a) 4.15 s

We start by noticing that:

- The horizontal motion of the skier is a uniform motion, with constant velocity

$v_x = 28 m/s$

and the distance covered along the horizontal direction in a time t is

$d_x = v_x t$

- The vertical motion of the skier is a uniformly accelerated motion, with initial velocity $u_y = 0$ and constant acceleration $g=9.8 m/s^2$ (where we take the downward direction as positive direction). Therefore, the vertical distance covered in a time t is

$d_y = \frac{1}{2}gt^2$

The time t at which the skier lands is the time at which the skier reaches the incline, whose slope is

$\theta = 36^{\circ}$ below the horizontal

This happens when:

$tan \theta = \frac{d_y}{d_x}$

Substituting and solving for t, we find:

$tan \theta = \frac{\frac{1}{2}gt^2}{v_x t}= \frac{gt}{2v_x}\\t = \frac{2v_x}{g}tan \theta = \frac{2(28)}{9.8} tan 36^{\circ} =4.15 s$

b) 143.6 m

Here we want to find the distance covered along the slope of the incline, so we need to find the horizontal and vertical components of the displacement first:

$d_x = v_x t = (28)(4.15)=116.2 m$