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statuscvo [17]
3 years ago
8

Why can beta particles pass through materials more easily than alpha particles?

Physics
2 answers:
zavuch27 [327]3 years ago
5 0

<span>Good Morning!
 
A) Beta particles are less energetic than alpha particles.
C) The beta particles are negatively charged;
D) Beta particles move much faster than alpha.
 -
B) The beta particles are smaller, so it is that they pass better.
 
hugs!</span>
sergeinik [125]3 years ago
5 0

Answer: Option (B) is the correct answer.

Explanation:

Alpha particles are helium atoms whereas beta particles are just electrons. Electrons are much lighter than alpha particles (which include both protons and neutrons).

Therefore, electrons can move quickly from one place to other. Also, an electron or beta particle is 8,000 times smaller than alpha particle.

Hence, we can conclude that beta particles pass through materials more easily than alpha particles because beta particles are smaller.




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Two identical space probes are orbiting Jupiter. Scientists determine that one of the space probes has a larger gravitational fo
galina1969 [7]

If the probes are identical, then the one that feels a larger gravitational
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If they're not identical, then the one with greater mass will feel more
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6 0
3 years ago
Read 2 more answers
What is the frequency if a wave that pases a given pount 22 times in 2 seconds
34kurt

The answer is B. 11 Hz

3 0
3 years ago
A porter can carry 40 bricks of 10 N load of each. He can carry up to 75m in 40 sec, calculate his power.​
alexira [117]

Answer:

750W

Explanation:

40×10= 400N

work done= force × distance

=400 × 75

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4 0
1 year ago
A proton, an alpha particle (a bare helium nucleus), and a singly ionized helium atom are accelerated through a potential differ
ra1l [238]

Answer:

The correct question is:

"Find the energy each gains"

The energy gained by a charged particle accelerated through a potential difference is given by

\Delta U = q\Delta V

where

q is the charge of the particle

\Delta V is the potential difference

For a proton,

q=+e=1.6\cdot 10^{-19}C

And since \Delta V=100 V

The energy gained by the proton is

\Delta U=(1.6\cdot 10^{-19})(100)=1.6\cdot 10^{-17}J

For an alpha particle,

q=+2e=3.2\cdot 10^{-19}C

Therefore, the energy gained is

\Delta U=(3.2\cdot 10^{-19})(100)=3.2\cdot 10^{-17}J

Finally, for a singly ionized helium nucleus (a helium nucleus that has lost one electron)

q=+e=1.6\cdot 10^{-19}C

So the energy gained is the same as the proton:

\Delta U=(1.6\cdot 10^{-19})(100)=1.6\cdot 10^{-17}J

6 0
3 years ago
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