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arlik [135]
3 years ago
15

The plain flight covers 400 miles in the first hour. As you approach the landing site, it takes you an hour to cover the last 20

0 miles. This a example of
Positive acceleration.

Velocity.

Instantaneous speed.

Negative acceleration.
Physics
1 answer:
tatyana61 [14]3 years ago
3 0

that is an example of negative acceleration because it is slowing down

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Non examples of kinetic energy
inn [45]

Answer:

Hydropower Plants. Hydropower plants are places where the generation of electricity takes place with the help of water. ...

Wind Mills. Windmills form one of the good examples of applications of kinetic energy. ...

Moving Car. ...

Bullet From a Gun. ...

Flying Airplane. ...

Walking & Running. ...

Cycling. ...

Rollercoasters.

Explanation:

,

6 0
3 years ago
Read 2 more answers
How much work, in Joules. is done when a pressure of 95.000 Pa changes a volume from 15 ma to 43 m2?
gayaneshka [121]

Answer:

-2.66 kJ

Explanation:

At constant pressure, work done is:

W = -P ΔV

W = -(95.000 Pa) (43 m² − 15 m²)

W = -2660 J

W = -2.66 kJ

5 0
4 years ago
Given: Q1 = +20 µc = 2.0 x 10-5 C
Feliz [49]
<span>6.7 x 10-11....Have a good day with a big fat A+

</span>
3 0
3 years ago
Read 2 more answers
In a Young's double-slit experiment, light of wavelength 500 nm illuminates two slits which are separated by 1 mm. The separatio
liubo4ka [24]

Answer:

The  value is  y  = 0.0025 \  m

Explanation:

From the question we are told that

   The  wavelength is  \lambda  =  500 \ nm

    The distance of separation is  d =  1\  mm  =  0.001 \ m

   The  distance from the screen is  D  =  5 \ m

Generally the separation between the adjacent bright fringe is mathematically represented as

       y  = \frac{D  *  \lambda }{ d}

=>    y  =  \frac{5 *  500 *10^{-9}}{0.001}

=>    y  = 0.0025 \  m

3 0
3 years ago
How much work done when .0080 C is moved through a potential difference of 1.5 V? Use W = qV. A.
grin007 [14]

Answer:

0.012 J

Explanation:

We are given:

q = 0.0080C

Potential difference =  1.5V

W=qV

Substituting the values into the equation:

W=0.0080*1.5= 0.012J

8 0
3 years ago
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