Answer:
what grade are you in so i can help
Explanation:
Answer : The work function of this metal is, 
Explanation : Given,
Wavelength of light = 
Formula used :

where,
E = work function of metal
h = Planck's constant = 
= threshold frequency
= wavelength of light
c = speed of light = 
Now put all the given values in this formula, we get the value of work function of this metal.



Therefore, the work function of this metal is, 
Answer:light waves carry energy parallel to the motion Of The wave, while sound waves carry energy perpendicular to it
Explanation:light waves carry energy parallel to the motion Of The wave while sound waves carry energy perpendicular to it
Answer:
The ratio between W2 and W1 is
p=1.5
Explanation:
The W2/W1 ratio equals the efficiency ratio, since the heat input is constant.
Initially, the Carnot efficiency is
1 - (Tc/Th)
1 - 400/800 = 0.50
After lowering Tc, the efficiency becomes
1 - (Tc/Th)
1 - 200/800 = 0.75
So to determine the ratio between W2 and W1
W2/W1 = 0.75/0.50 = 1.5
Answer:
i) b. 14.3 Hz
ii) d. 0.4625 m/s
Explanation:
f = c / λ
f = frequency
c = speed
λ = wavelength
first question:
the given values,
λ = 2.17 m
c = 31 m/s
f = c / λ
f = 31 / 2.17
f = 14.28
∴ f = 14.3 Hz
second question:
given,
λ = 0.25 m
f = 1.85 Hz
f = c / λ
rearranging,
c = f × λ
c = 1.85 × 0.25
c = 0.4625
∴ c = 0.4625 m/s
(love your username, btw.)