Answer:
4510 J
Explanation:
To calculate the energy of the water, you need to use the following equation:
Q = mcΔT
In this equation,
-----> Q = energy/heat (J)
-----> m = mass (g)
-----> c = specific heat capacity (J/g°C)
-----> ΔT = change in temperature (°C)
First, you need to determine the mass of the water. To do this, you need to multiply the given volume by the density of water (1.00 g/mL).
100.0 mL H₂O 1.00 g
------------------------ x ------------ = 100.0 g H₂O
1 mL
Now, you can plug the given values into the equation and solve for "Q" (Q =
). The final answer should have 3 significant figures to match the given values with the lowest number of sig figs.
Q = ? J c = 4.18 J/g°C
m = 100.0 g ΔT = 32.0 °C - 21.2 °C = 10.8 °C
Q = mcΔT
Q = (100.0 g)(4.18 J/g°C)(10.8 °C)
Q = 4510 J
Answer:
8,588,461,537
Explanation:
Since the atoms are arranged in a straight line in contact with each other what we have to do is divide the length into the diameter of copper (2r) to obtain the number of atoms in the 223.3 cm of copper wire, and from there we can figure how many times we wil have to divide it to answer our question.
diameter = 2 x( 1.3 x 10⁻¹⁰ m) = 2.6 x 10⁻¹⁰ m
The number of diameters in 223.3 cm ( 2.233 m ) which is the number of atoms in this length:
2.233 m / 2.6 x 10⁻¹⁰ m/atom = 8,588,461,538 atoms
So we will have to divide it 8,588,461,537 ( one minus because we want to sepate 8,588,461,538 atoms )
This is a problem where we have to work with integers and not decimals since we can not speak for example of 0.5 individual atoms
Hi :)
a. the reactants are zinc and copper oxide
b. the products are zinc oxide and copper
c. the elements are zinc, oxygen, and copper
d. the compounds are copper oxide and zinc oxide
hope this helps.