The answer is 975S because u add all ofthem
Answer:
1. Iodine is reduced
2. Iodine is reduced
3. Iodine is oxidized
Explanation:
1. Oxidation number goes from 0 to -16
(oxidation number decreases = reduction)
2. Oxidation number goes from 0 to -6
3. Oxidation number goes from +2 to 0.
(oxidation number increases; the atom loses electrons = oxidation)
C
Mol x Avogadro's number
Mol : mass / molar mass
Avogadro's no: 6.02E+23
hello good person