Answer:
The mass of SO2 will be equal to the sum of the mass of S and O2.
Explanation:
This can be explained by the <em>Law of Conservation of Mass</em>. This law states that mass can neither be created nor destroyed. Knowing this, we can say that the reactants of a chemical reaction must be equal to the products.
In this case, the reactants Sulfur (S) and Oxygen (O2) must equal the mass of the product Sulfur Dioxide (SO2). Therefore, the statement <em>"The mass of SO2 will be equal to the sum of the mass of S and O2" </em>is correct.
It is beacuse the ions in the melted or aqueous ionic compound is mobile and can freely move through the fluid and conduct electricity.
<span>The answer is (3) esterification. Note that deposition, distillation and sublimation are not chemical changes, they are physical changes, so you can solve this question by elimination if you know that. Regarding sterification it is a well known chemical reaction that consists on the formation of esters from carboxilic acids.</span>
The number of mole of nitrogen gas, N₂, needed to produce 150 g of ammonia, NH₃ is 4.41 moles
<h3>How to determine the mole of NH₃ produced </h3>
- Mass of NH₃ = 150 g
- Molar mass of NH₃ = 14 + (3×1) = 17 g/mol
Mole = mass /molar mass
Mole of NH₃ = 150 / 17
Mole of NH₃ = 8.82 moles
<h3>How to determine the mole of N₂ needed </h3>
Balanced equation
N₂ + 3H₂ —> 2NH₃
From the balanced equation above,
2 moles of NH₃ were produced by 1 mole of N₂.
Therefore,
8.82 moles of NH₃ will be produced by = 8.82 / 2 = 4.41 moles of N₂.
Thus, 4.41 moles of N₂ is needed for the reaction.
Learn more about stoichiometry:
brainly.com/question/14735801
Answer:
3.53*
Explanation:
![K_{c} =\frac{[HI]^{2}[Cl_{2}] }{[HCl]^{2}}=\frac{[5.6*10^{-16} ]^{2} [0.0019]}{[0.13]^{2} }=3.53*10^{-32}](https://tex.z-dn.net/?f=K_%7Bc%7D%20%3D%5Cfrac%7B%5BHI%5D%5E%7B2%7D%5BCl_%7B2%7D%5D%20%7D%7B%5BHCl%5D%5E%7B2%7D%7D%3D%5Cfrac%7B%5B5.6%2A10%5E%7B-16%7D%20%5D%5E%7B2%7D%20%5B0.0019%5D%7D%7B%5B0.13%5D%5E%7B2%7D%20%7D%3D3.53%2A10%5E%7B-32%7D)
Kc is the equilibrium constant calculated as the ration of products over reactants with their stoichiometric coefficients as their exponents. So the balanced chemical equation is important. Solids do not form part of the Kc expression, they do not affect the equilibrium constant which is why Iodine is not part of the calculations
