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Margarita [4]
3 years ago
10

What is the definition of input force?

Physics
2 answers:
Len [333]3 years ago
6 0

Answer:

The input force (effort) is the amount of effort used to push down on a rod, or pull on a rope in order to move the weight. In this example, the force the little guy is using to pull the elephant is the input force.

andrezito [222]3 years ago
5 0

Answer:

The input force (effort) is the amount of effort used to push down on a rod, or pull on a rope in order to move the weight. In this example, the force the little guy is using to pull the elephant is the input force.

Explanation:

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In multicellular organisms, which choice ranks the level of organization from simplest to increasingly more complex?
Andreyy89

Answer:

<em>The answer is C.</em>

Explanation:

Cells are the smallest organisms and makes up all living thing or being. The tissues are made of cells. The organs are made of tissues. The organ systems are made of organs. Therefore the order is C. cells, tissues, organs, and organ systems.

3 0
3 years ago
To measure the height of a building without a ruler or tape measure, an engineer drops a rock off the top of the building and fi
serg [7]

The relevant equation we can use in this problem is:

h = v0 t + 0.5 g t^2

where h is height, v0 is initial velocity, t is time, g is gravity

 

Since it was stated that the rock was drop, so it was free fall and v0 = 0, therefore:

h = 0 + 0.5 * 9.81 m/s^2 * (4.9 s)^2

<span>h = 117.77 m</span>

6 0
3 years ago
The momentum of a car 54,400 kg * m/s. If the car weighs 16,680N what is the velocity of the car
wariber [46]

G=mg=>m=G/g=16680/9.8=1702 kg

p=mv=>v=p/m=54400/1702=32 m/s

6 0
3 years ago
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What day of the year is solar time the same as sidereal time?
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Answer:

I think the answers March 21

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A model rocket fired vertically from the ground ascends with a constant vertical acceleration of 52.7 m/s2 for 1.41 s. its fuel
olya-2409 [2.1K]
For rectilinear motions, derived formulas all based on Newton's laws of motion are formulated. The equation for acceleration is

a = (v2-v1)/t, where v2 and v1 is the final and initial velocity of the rocket. We know that at the end of 1.41 s, the rocket comes to a stop. So, v2=0. Then, we can determine v1.

-52.7 = (0-v1)/1.41
v1 = 74.31 m/s

We can use v1 for the formula of the maximum height attained by an object thrown upwards:

Hmax = v1^2/2g = (74.31^2)/(2*9.81) = 281.42 m

The maximum height attained by the model rocket is 281.42 m.

For the amount of time for the whole flight of the model rocket, there are 3 sections to this: time at constant acceleration, time when it lost fuel and reached its maximum height and the time for the free fall.

Time at constant acceleration is given to be 1.41 s. Time when it lost fuel covers the difference of the maximum height and the distance travelled at constant acceleration.

2ax=v2^2-v1^2
2(-52.7)(x) = 0^2-74.31^2
x =52.4 m (distance it covered at constant acceleration)
Then. when it travels upwards only by a force of gravity,
d = v1(t) + 1/2*a*t^2
281.42-52.386 = (0)^2+1/2*(9.81)(t^2)
t = 6.83 s (time when it lost fuel and reached its maximum height)

Lastly, for free falling objects, the equation is
t = √2y/g = √2(281.42)/9.81 = 7.57 s

Therefore, the total time= 1.41+6.83+7.57 = 15.81 s

6 0
3 years ago
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