Answer:
Explanation:
mass of car, m = 1022 kg 
mass of truck, M = 1620 kg 
initial velocity of truck, U = 14.5 m/s 
initial velocity of car, u = 0 m/s 
Let the final velocity of car is v and the final velocity of truck is V. 
Collision is elastic, so the coefficient of restitution, e = 1 
Use conservation of momentum 
initial momentum of car + initial momentum of truck = final momentum of car + final momentum of truck 
m x u + M x U = m x v + M x V 
0 + 1620 x 14.5 = 1022 v + 1620 V 
23490 = 1022 v + 1620 V ..... (1) 
Use the formula of coefficient of restitution

1 (14.5 - 0) = v - V
14.5 = v - V 
V = v - 14.5 .... (2) 
Put in equation (1) 
23490 = 1022 v + 1620 (v - 14.5) 
23490 = 1022 v + 1620 v - 23490 
46980 = 2642 v 
v = 17.8 m/s 
Put in equation (2) 
V = 17.8 - 14.5 
V = 3.3 m/s 
Thus, the speed of car is 17.8 m/s and the velocity of truck is 3.3 m/s after collision.