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3 years ago

What is the mechanical advantage of the wheel and axle shown below?

Physics

2 answers:

Salsk061 [2.6K]3 years ago

7 0

Answer:

Mechanical advantage of the wheel and axle is 32.5

Explanation:

Given that,

The radius of the axle, $r_a=0.8\ cm$

The radius of wheel , $r_w=26\ cm$

We need to find the mechanical advantage of the wheel and axle. It can be calculated as :

$MA=\dfrac{r_w}{r_a}$

$MA=\dfrac{26}{0.8}$

MA = 32.5

So, the mechanical advantage of the wheel and axle shown below is 32.5 . Hence, this is the required solution.

BigorU [14]3 years ago

6 0

The correct answer is A. 32.5

Mechanical advantage is the ratio of force that is input into a machine to the force output.

Mechanical advantage of a wheel and axle is calculated by dividing the radius of the wheel by that of the axle.

MA=R/r where R is the radius of the wheel and r is the radius of the axle.

Substituting for the values in the question gives:

MA=26cm/0.8cm

=32.5

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kompoz [17]

Answer:

1.312 x 10⁻¹² J/nucleon

Explanation:

mass of ¹³⁶Ba = 135.905 amu

¹³⁶Ba contain 56 proton and 80 neutron

mass of proton = 1.00728 amu

mass of neutron = 1.00867 amu

mass of ¹³⁶Ba = 56 x 1.00728 amu + 80 x 1.00867 amu

= 137.10128 amu

mass defect = 137.10128 - 135.905

= 1.19628 amu

mass defect = 1.19628 x 1.66 x 10⁻²⁷ Kg

= 1.9858 x 10⁻²⁷ Kg

speed of light = 3 x 10⁸ m/s

binding energy,

E = mass defect x c²

E = 1.9858 x 10⁻²⁷ x (3 x 10⁸)²

E = 17.87 x 10⁻¹¹ J/atom

now,

binding energy per nucleon = $\dfrac{17.87\times 10^{-11}}{136}$

= 0.1312 x 10⁻¹¹ J/nucleon

= 1.312 x 10⁻¹² J/nucleon

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A machine

In-s [12.5K]

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Explanation:

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$W = F*d$

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W = work [J] (units of Joules)

F = force [N] (units of Newton)

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We need to bear in mind that the force can be calculated by multiplying the mass by the gravity acceleration.

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P = power [W] (units of watts)

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