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Stella [2.4K]
3 years ago
13

The Earth is approximately 150 million kilometers away from the Sun. If light travels at a speed of approximately 300,000 kilome

ters per second, about how long does it take for light from the Sun to reach the Earth?
Physics
2 answers:
Firdavs [7]3 years ago
7 0

Answer:

about 10 minutes

Explanation:

study island

evablogger [386]3 years ago
4 0

The correct answer to the question is 8.33 minutes.

CALCULATION:

The distance of earth from sun s = 150 million km.

We know one million = 10 lakh = 10^6

Also 1 km = 10^3\ m

Hence, the distance s = 150\times 10^6\times 10^3\ m

                                     = 15\times 10^{10}\ m

The speed of light c = 300,000 km per second

                                  = 3\times 10^8\ m/s

We are asked to calculate the time.

The time of the reaching earth is calculated as -

                                         time=\ \frac{distance}{velocity}

                                         t=\ \frac{s}{c}

                                                =\ \frac{15\times 10^{10}} {3\times 10^8}\ second

                                                =\ 500\ seconds

We know one minute = 60 second.

Hence, 500  seconds = \frac{500}{60}\ minute

                                     = 8.33\ minute       [ans]

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Using snell's law. Determine what angle a light wave bends at when it
Alex777 [14]

Answer:

Angle of refraction is 23° .

Explanation:

\frac{ \sin(0w) }{ \sin(0a) }  =  \frac{n \: a}{n \: w}

\frac{ \sin(30) }{ \sin \: 0a }  =  \frac{1.3}{1.0}

\sin \: 0w \:  =  \:  \frac{ \sin(30) }{1.3}

= 0.3846153846

\sin^{ - 1} (0.3846153846

0w \:  =  \: 23 ^{o}

7 0
3 years ago
A football punter wants to kick the ball so that it is in the air for 4.5 s and lands 50 m from where it was kicked. Assume that
irakobra [83]

Answer:

(a) The angle of projection is 63 degree.

(b) The velocity of projection is 24.5 m/s.

Explanation:

Height, h = 1 m

horizontal distance, d = 50 m

time, t = 4.5 s

Let the initial velocity is u and the angle is A.

(a) Horizontal distance = horizontal velocity x time

50 = u cos A x 4.5

u cos A = 11.1 .....(1)

Use second equation of motion in vertical direction

h = u t + 0.5 gt^2\\\\- 1 = u sin A \times 4.5 - 0.5 \times 9.8\times 4.5^2\\\\u sin A = 21.8 ..... (2)

Divide (2) by (1)

tan A = 1.97

A = 63 degree

(b) Substitute the value of A in equation (2)

u x sin 63 = 21.8

u = 24.5 m/s

7 0
3 years ago
Thường ngày an đi bộ từ nhà đến trường mất 15 phút biết quãng đường từ nhà đến trường dài 1.5 km tính vận tốc đi thường ngày của
DedPeter [7]

Answer:

Speed in kilometer/hour = 6 kilometer / hour

Explanation:

Given;

Time taken to cover distance = 15 minute = 15 /60 = 0.25 hour

Distance of school = 1.5 kilometer

Find:

Speed in kilometer/hour

Computation:

Speed in kilometer/hour = Distance / Time

Speed in kilometer/hour = Distance of school / Time taken to cover distance

Speed in kilometer/hour = 1.5 / 0.25

Speed in kilometer/hour = 6 kilometer / hour

7 0
3 years ago
A car travels 480 km in 12 hr. what is its velocity
Svet_ta [14]

Answer:

Explanation:

velocity=s/t

given distance is 480 km we have to convert it into meter because the unit of distance is meter

1 km=1000 m

480 km=480000 m =4.8*10^5

1 hour= 3600 s

12 hour =43200 s  

now velocity=s/t

v=4.8*10^5/43200

v=11.11 m/s

5 0
3 years ago
Read 2 more answers
Assume that the speed of light in a vacuum has the hypothetical value of 18.0 m/s. A car is moving at a constant speed of 14.0 m
Oksi-84 [34.3K]

Answer:

Observed time, t = 5.58 s  

Explanation:

Given that,

Speed of light in a vacuum has the hypothetical value of, c = 18 m/s

Speed of car, v = 14 m/s along a straight road.

A home owner sitting on his porch sees the car pass between two telephone poles in 8.89 s.

We need to find the time the driver of the car measure for his trip between the poles. The relation between real and observed time is given by :

T=\dfrac{t}{\sqrt{1-\dfrac{v^2}{c^2}} }

t is observed time.

t=T\times \sqrt{1-\dfrac{v^2}{c^2}} \\\\t=8.89\times \sqrt{1-\dfrac{14^2}{18^2}} \\\\t=5.58\ s

So, the time observed by the driver of the car measure for his trip between the poles is 5.58 seconds.

4 0
3 years ago
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