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3 years ago

What component in a circuit does this symbol represent?

Physics

2 answers:

Andreas93 [3]3 years ago

5 0

Answer:

The given symbol is of DC power source

Option A is incorrect because in ammeter a letter A is written inside a circle.

Similarly, Option B is incorrect because in voltmeter V is written inside a circle

Option C and D are incorrect

Option E is correct it is a DC power source.

It is a Dc power source the left hand side is positive side and the right line is the negative side.

vladimir2022 [97]3 years ago

5 0

Option (e) is correct. The symbol shown in the figure represents a DC power source of an electrical circuit.

Explanation:

An electrical circuit is a proper arrangement of the different electrical components that drive power or energy from the voltage or a current source and operate according to its nature.

The different components used in a circuit are categorized into two broad categories. Active components and the passive components. The components that provide energy to the circuit are called as the active components and the component that derive energy from the active components are termed as the passive components.

The ammeter, voltmeter etc. are the devices that are used to measure the current and the voltage supplied to the circuit. An AC or DC power source supply the power to the circuit.

The component shown in the diagram represents a DC power source. The AC power source is represented by a zigzag line in a circle whereas the ammeter and voltmeter are represented by their letter A or V in a circle.

Thus, option (e) is correct. The symbol shown in the figure represents a DC power source of an electrical circuit.

Learn More:

1. Net force acting on the refrigerator brainly.com/question/4033012

2. The block that has the greater rise in temperature due to addition of heat brainly.com/question/3063912

3. Electric shock happens when brainly.com/question/3059888

Answer Details:

Grade: Middle School

Subject: Physics

Chapter: Electricity

Keywords:

components, switch, power supply, source, active, passive, ammeter, voltmeter, represents, energy supply, current, voltage.

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Answer:

Part A)

t(1) > t(2), the stone thrown 30 above the horizontal spends more time in the air.

Part B)

x(f1) > x(f2), the first stone will land farther away from the building.

Explanation:

Part A)

Let's use the parabolic motion equation to solve it. Let's define the variables:

y(i) is the initial height, it is a constant.
y(f) is the final height, in our case is 0
v(i) is the initial velocity (v(i)=16 m/s)
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θ2 is the first angle, -30°

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For the second stone

$0=y_{i2}+16*sin(-30)t_{2}-4.905t_{2}^{2}$

$0=y_{i2}-8t_{2}-4.905t_{2}^{2}$ (2)

If we solve the equation (1) we will have:

$t_{1}=\frac{-8\pm \sqrt{64+19.62*y_{i}}}{-9.81}$

We can do the same procedure for the equation (2)

$t_{1}=\frac{8\pm \sqrt{64+19.62*y_{i}}}{-9.81}$

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Therefore, t(1) > t(2), it means that the stone thrown 30 above the horizontal spends more time in the air.

Part B)

We can use the equation of the horizontal position here.

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$x_{f1}=x_{i1}+vcos(30)t_{1}$

$x_{f1}=0+13.86*t_{1}$

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$x_{1}=13.86*t_{2}$

Knowing that t(1) > t(2) then x(f1) > x(f2)

Therefore, the first stone will land farther away from the building.

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