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tester [92]
3 years ago
9

(a) At a distance of 0.200 cm from the center of a charged conducting sphere with radius 0.100 cm, the electric field is 480 N&g

t;C. What is the electric field 0.600 cm from the center of the sphere
Physics
1 answer:
yan [13]3 years ago
6 0

Answer:

E = 53.3 N/C

Explanation:

The charge of the sphere can be found by Gauss’ Law:

\int\vec{E}d\vec{a} = \frac{Q_{encl}}{\epsilon_0}

We will draw an imaginary spherical surface around the original sphere with radius 0.2 cm. The integral in the left-hand side is the area of this surface, therefore no need to take the integral. The right-hand side is equal to the total charge enclosed by this imaginary surface.

E2\pi r^2 = \frac{Q_{enc}}{\epsilon_0}\\(480)4\pi(0.002)^2 = \frac{Q}{8.8\times 10^{-12}}\\Q = 2.12\times 10^{-13}

Now that we have found the charge of the sphere, we can now apply Gauss’ Law again to find the E-field 0.006 m from the center.

We will draw our second imaginary spherical surface with a radius 0.006 m.

E4\pi r^2 = \frac{Q}{\epsilon_0}\\E4\pi(0.006)^2 = \frac{2.12 \times 10^{-13}}{\epsilon_0}\\E = 53.3~{\rm N/C}

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A Carnot engine operates with an efficiency of 26.0% when the temperature of its cold reservoir is 281 K. Assuming that the temp
VLD [36.1K]

Answer:

The temperature of cold reservoir should be 246.818 K for efficiency of 35%

Explanation:

In first case we have given efficiency of Carnot engine = 26 % = 0.26

Temperature of cold reservoir T_L=281K

We know that efficiency of Carnot engine is given by

\eta =1-\frac{T_L}{T_H}

0.26 =1-\frac{281}{T_H}

T_H=379.72K

For second Carnot engine efficiency is given as 35% = 0.35

And temperature of hot reservoir is same so T_H=379.72K

So 0.35=1-\frac{T_L}{379.72}

T_L=246.818K

So the temperature of cold reservoir should be 246.818 K for efficiency of 35%

4 0
3 years ago
Which of the following is an impact of trampling of beach grass by humans and vehicles?
grigory [225]
Increase in sea water pollution
6 0
3 years ago
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nirvana33 [79]

Answer:

A

Explanation:

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5 0
3 years ago
A ball rolls for 8 seconds and travels 24 meters. How fast was it traveling?
belka [17]

Answer:

The speed of the ball was, v = 3 m/s

Explanation:

Given data,

The time period of the ball, t = 8 s

The distance the ball rolled, d = 24 m

The velocity of an object is defined as the object's displacement to the time taken. The formula for the velocity is,

                              v = d / t      m/s

Substituting the given values in the above equation,

                               v = 24 / 8

                                  = 3 m/s

Hence, the speed of the ball was, v = 3 m/s

8 0
3 years ago
Say I have a series circuit with 20v and four 65 ohm resistors, what is the current in each resistor?
Komok [63]
Data:

E = 20 V
R_{1} = 65\Omega
R_{2} = 65\Omega
R_{3} = 65\Omega
R_{4} = 65\Omega

<span>Now that we have all the values ​​we need properly identified, simply calculate the equivalent total resistance of the circuit and the intensity of the total electric current using the Ohm's Law:

</span>R_{T} =  R_{1} + R_{2} + R_{3} + R_{4}
R_{T} = 65 + 65 + 65+ 65
R_{T} = 260\Omega

<span>Like this:
</span>
I_{T} =  \frac{E}{ R_{T} }

I_{T} = \frac{20}{ 260 }
I_{T} = 0,076923076...

\boxed{\boxed{I_{T} \approx 0,07A}} 
Answer:
<span>The intensity of the total electric current 
</span>\boxed{\boxed{I_{T} \approx 0,07A}} 

P.S:. Since the association is in series, the current of 0.07A is the same for all resistors.
4 0
3 years ago
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