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Brrunno [24]
3 years ago
14

A reaction occurs when solid X is placed into solution Y. As a result, the temperature of the new solution increases by 3°C.

Chemistry
1 answer:
zzz [600]3 years ago
6 0
It increases the number of molecular collisions.
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The empirical formula of styrene is CH; its molar mass is 104.1 g/mol. What is the molecular formula of styrene?
Natalija [7]
You got the answer correct. If you would double check
given:C (12 g/mol) H (1 g/mol). 

12(8) + 1(8) = 104 g/mol

and for C2H4
12(2)+1(4) = 28g/mol

Also, chemical formula of styrene is<span> C6H5CH=CH2.</span>
7 0
3 years ago
Read 2 more answers
What would happen if I removed a resistor from a parallel circuit? What would
barxatty [35]

Answer:

In a parallel circuit, current divides through resistors and current might be different depending upon the resistor and all resistors have the same potential difference. Therefore, if a parallel resistor was removed then the total resistance of the circuit will increase.

7 0
2 years ago
1. the mass of one electron is
kupik [55]

Answer:

Mass of one electron is 9.1 × 10⁻³¹ kg

Mass of one proton is 1.673 × 10⁻²⁷ Kg

Mass of one neutron is 1.675 × 10⁻²⁷ Kg

 

<u>-TheUnknownScientist</u><u> 72</u>

4 0
2 years ago
A 10.0 gram sample of Fe contains how many miles of Fe
Dafna1 [17]

Answer:

1.7857 moles

Explanation:

moles=mass/Mr

10/56=1.7857

moles of iron =1.7857

4 0
2 years ago
Using the standard reduction potentials, Pb 2+(aq) + 2e– =&gt; Pb(s), E° = –0.13 V Fe 2+(aq) + 2e– =&gt; Fe(s), E° = –0.44 V Zn
mojhsa [17]

Answer:

Pb(s), Fe(s) and Zn(s) will reduce Mn^{3+} to Mn^{2+}

Fe(s) and Zn(s) will reduce Cr^{3+} to Cr

Explanation:

Standard reduction potential denotes ability to consume electrons from another species.

Hence, higher the standard reduction potential, higher will be the ability to oxidize another species.

Metal with E_{red}^{0} value lower than 1.51 V will donate electron to Mn^{3+} and thus reduces Mn^{3+} to Mn^{2+}.

So, Pb(s), Fe(s) and Zn(s) will reduce Mn^{3+} to Mn^{2+}.

Metal with E_{red}^{0} value lower than -0.40 V will donate electron to Cr^{3+} and thus reduces Cr^{3+} to Cr.

So, Fe(s) and Zn(s) will reduce Cr^{3+} to Cr.

6 0
3 years ago
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