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Fittoniya [83]
3 years ago
9

A charge of 4.5 × 10-5 C is placed in an electric field with a strength of 2.0 × 104 . If the charge is 0.030 m from the source

of the electric field, what is the electric potential energy of the charge?
Physics
1 answer:
snow_tiger [21]3 years ago
8 0

Answer:

The electrical potential energy is 0.027 Joules.

Explanation:

The values from the question are

charge (q) = 4.5 \times 10^{-5} C

Electric Field strength (E) = 2.0 \times 10^{4} N/C

Distance from source (d) = 0.030 m

Now the formula for the electrical potential energy (U) is given by

U = q \times E \times d

So now insert the values to find the answer

U = 4.5 \times 10^{-5} C \times 2.0 \times 10^{4} N/C \times 0.030 m

On further solving

U = 0.027 J

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When two surfaces slide against each other, a force called friction makes them stick very slightly together. Smooth surfaces, like ice and glass, are easy to slide over. They create very little friction. Rough surfaces like rock and sand create much more friction, and are easy to grip on to.

hope it helps...!!!

7 0
2 years ago
Explain the change of frequency of the wave if the tension of the string is increased​
jek_recluse [69]

Answer:

Increasing the tension on a string increases the speed of a wave, which increases the frequency (for a given length). Pressing the finger at different places changes the length of string, which changes the wavelength of standing wave, affecting the frequency.

Explanation:

8 0
2 years ago
A 65.0-kg runner has a speed of 5.20 m/s at one instant dur- ing a long-distance event. (a) What is the runner’s kinetic energy
vladimir2022 [97]

Answer:

a)KE=878.8 J

b)W=2636.4 J      

Explanation:

Given that

mass ,m = 65 kg

Initial speed ,u = 5.2 m/s

a)

We know that kinetic energy KE is given as follows

KE=\dfrac{1}{2}mu^2

m=mass

u=velocity

Now by putting the values in the above equation we get

KE=\dfrac{1}{2}\times 65\times 5.2^2\ J

KE=878.8 J

b)

We know that

Work done by all forces = Change in the kinetic energy

The final velocity , v= 2 u = 2 x 5.2 m/s

v= 10.4 m/s

W=\dfrac{1}{2}mv^2-\dfrac{1}{2}mu^2

Now by putting the values in the above equation we get

W=\dfrac{1}{2}\times 65\times 10.4^2-\dfrac{1}{2}\times 65\times 5.2^2\ J

W=2636.4 J

a)KE=878.8 J

b)W=2636.4 J

8 0
3 years ago
Zero, a hypothetical planet, has a mass of 5.8 x 1023 kg, a radius of 2.7 x 106 m, and no atmosphere. a 10 kg space probe is to
Tom [10]
To answer these questions just use the equations for potential energy using the mass and heights described. the potential energy at the prescribed heights = the initial kinetic energy required to reach that height.

Make sure you calculate the force of gravity on the surface using the radius of the planet.
5 0
3 years ago
A bat can detect small objects, such as an insect, whose size is approximately equal to one wavelength of the sound the bat make
blsea [12.9K]

Answer:

6.136 mm

Explanation:

given,

frequency emitted by the bat = 5.59 x 10⁴ Hz

speed of sound = 343 m/s

smallest insect bat can hear  will be equal to the wavelength  of the sound the bat make.

\lambda = \dfrac{v}{f}

\lambda = \dfrac{343}{5.59\times 10^4}

\lambda = 6.136\times 10^{-3}}

λ = 6.136 mm

so, the smallest size of insect that bat can hear is equal to 6.136 mm

8 0
3 years ago
Read 2 more answers
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