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vichka [17]
3 years ago
12

How does a sound wave transfer energy to your ears?

Physics
1 answer:
inessss [21]3 years ago
4 0

Answer:

I think it's C!

Explanation:

Sound waves travel at 343 m/s through the air and faster through liquids and solids. The waves transfer energy from the source of the sound, e.g. a drum, to its surroundings. Your ear detects sound waves when vibrating air particles cause your eardrum to vibrate. The bigger the vibrations the louder the sound.

Hope this helps!

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A particle leaves the origin with a speed of 3.6 106 m/s at 34 degrees to the positive x axis. It moves in a uniform electric fi
Andrej [43]

Answer:

E = -4556.18 N/m

Explanation:

Given data

u = 3.6×10^6 m/sec

angle = 34°

distance x = 1.5 cm = 1.5×10^-2 m  (This data has been assumed not given in

Question)

from the projectile motion the horizontal distance traveled by electron is

x = u×cosA×t

⇒t = x/(u×cos A)

We also know that force in an electric field is given as

F = qE

q= charge , E= strength of electric field

By newton 2nd law of motion

ma = qE

⇒a = qE/m

Also, y = u×sinA×t - 0.5×a×t^2

⇒y = u×sinA×t - 0.5×(qE/m)×t^2

if y = 0 then

⇒t = 2mu×sinA/(qE) = x/(u×cosA)

Also, E = 2mu^2×sinA×cosA/(x×q)

Now plugging the values we get

E = 2×9.1×10^{-31}×3.6^2×10^{12}×(sin34°)×(cos34°)/(1.5×10^{-2}×(-1.6)×10^{-19})

E = -4556.18 N/m

4 0
2 years ago
Jane, looking for tarzan, is running at top speed (6.8 m/s) and grabs a vine hanging vertically from a tall tree in the jungle.
erica [24]
Jane's mechanical energy at any time is
E=U+K
where U=mgh is the potential energy, while K= \frac{1}{2} mv^2 is the kinetic energy.

Initially, Jane is on the ground, so the altitude is h=0 and the potential energy is zero: U=0. She's running with speed v, so she has kinetic energy only:
E=K= \frac{1}{2} mv^2
Then she grabs the vine, and when she reaches the maximum height h, her speed is zero: v=0, and so the kinetic energy becomes zero: K=0. So now her mechanical energy is just potential energy:
E=U=mgh

But E must be conserved, so the initial kinetic energy must be equal to the final potential energy:
\frac{1}{2}mv^2=mgh
from which we can find h, the maximum height Jane can reach:
h= \frac{v^2}{2g}= \frac{(6.8 m/s)^2}{2\cdot 9.81 m/s^2}=2.36 m
6 0
3 years ago
How far did a car travel if it was on the road for 55.2s and it traveled at an average speed of 55m/s
pantera1 [17]
The car traveled 1.00363 kilometers in the 55.2s and the speed of 55m/s
3 0
2 years ago
A small fish is dropped by a pelican that is rising steadily at 0.500 m/s. How far below the pelican is the fish after 2.50 s?
sesenic [268]
Refer to the diagram shown below.

h = original height of the pelican when the fish is dropped (not relevant).
S =  distance traveled by the fish as a function of time, measured upward.
u = 0.5 m/s, the upward velocity with which the fish is dropped.
g = 9.8 m/s², the acceleration due to gravity.

Use the following equation:
S = ut + (1/2)gt²

S = (0.5 m/s)*(2.5 s) + 0.5*(-9.8 m/s²)*(2.5 s)²
   = -29.375 m

The negative sign means that the fish drops by  29.375 m from the original height of h.

Answer: The fish is 29.375 m below where the pelican dropped it after 2.5 s.

7 0
3 years ago
What instrument is normally used to measure atmospheric pressure?
Anuta_ua [19.1K]
B. Barometer is used to measure atmospheric pressure.
6 0
2 years ago
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