Answer:
t = 0.37 seconds
Explanation:
t = (1/4)T
Maximum acceleration is;
a_max = Aω²
In simple harmonic motion, we know that v_max = Aω
Thus, a_max = v_max•ω
ω = a_max/v_max
We know that Period is given by;
T = 2π/ω
From initially, t = (1/4)T so, T = 4t
Thus, 4t = 2π/(a_max/v_max)
t = (2π/4)(v_max/a_max)
We are given;
Maximum velocity;v_max = 1.47 m/s
Max acceleration;a_max =6.24 m/s²
Thus,
t = (2π/4)(1.47/6.24)
t = 0.37 seconds
Answer:
The required IVP is;
u'' + 196u = 0
where;
u(0) = 0 and
u'(0) = -10
Explanation:
See the attached for explanation
lf a heavy point mass is suspended by a weightless, inextensible and perfectly flexible string from a rigid support, then this arrangement is called simple pendulum.
In practice, however, these requirements cannot be fulfilled. So we use a practical pendulum.
A practical pendulum consists of a small metallic solid sphere suspended by a fine silk thread from a rigid support. This is the practical simple pendulum which is nearest to the ideal simple pendulum.
Note :
The metallic sphere is called the bob.
When the bob is displaced slightly to one side from its mean position and released, it oscillates about its mean position in a vertical plane.
Answer:
534 j
Explanation:
100 lbs = 45.359 kg
work = F * d
= 45.359 * 9.81 * 1.2 = ~ 534 j
