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Andre45 [30]
3 years ago
14

Peak hydraulic systems demands may be met by the use of what ?

Physics
2 answers:
nikklg [1K]3 years ago
8 0
By the use of a Accumulators
Ne4ueva [31]3 years ago
7 0

Answer:

<u><em>The answer is</em></u>: <u>Variable displacement pump.</u>

<u />

Explanation:

The pump <em>increases the hydraulic pressure to the nominal value required by the system. </em>

<u>Variable displacement pump</u>: <em>A variable displacement pump has a fluid outlet that varies to meet the system's pressure demands. The pump output is automatically changed to a compensating pump inside the pump. </em>

Variable displacement pumps are independent of the number of revolutions per minute of the pump as the amount of liquid displaced depends on the needs of the system.

<u><em>The answer is</em></u>: <u>Variable displacement pump.</u>

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Please answer I will give good rating and mark brainlest
lina2011 [118]
The answer is C. You must divide your wavelength and your frequency to get your answer.
8 0
3 years ago
The propeller of a World War II fighter plane is 2.30 m in diameter. (a) What is its angular velocity in radians per second if i
Sergio [31]

Answer with Explanation:

We are given that

Diameter of fighter plane=2.3 m

Radius=r=\frac{d}{2}=\frac{2.3}{2}=1.15 m

a.We have to find the angular velocity in radians per second if it spins=1200 rev/min

Frequency=\frac{1200}{60}=20 Hz

1 minute=60 seconds

Angular velocity=\omega=2\pi f

Angular velocity=2\times \frac{22}{7}\times 20=125.7 rad/s

b.We have to find the linear speed of its tip at this  angular velocity if the plane is stationary on the tarmac.

v=r\omega=1.15\times 125.7=144.56 m/s

c.Centripetal acceleration=\omega^2 r=(125.7)^2(1.15)=18170.56 m/s^2

Centripetal acceleration==\frac{18170.56\times g}{9.81}=1852.25 g m/s^2

7 0
3 years ago
What is the energy in joules of a mole of photons associated with visible light of wavelength 486 nm?
ivann1987 [24]

Answer:

2.46\cdot 10^5 J

Explanation:

The energy of a single photon is given by:

E=\frac{hc}{\lambda}

where

h is the Planck constant

c is the speed of light

\lambda is the wavelength

For the photon in this problem,

\lambda=486 nm=4.86\cdot 10^{-7}m

So, its energy is

E_1=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{4.86\cdot 10^{-7}m}=4.09\cdot 10^{-19} J

One mole of photons contains a number of photons equal to Avogadro number:

N_A = 6.022\cdot 10^{23}

So, the total energy of one mole of photons is

E=N_A E_1 = (6.022\cdot 10^{23})(4.09\cdot 10^{-19} J)=2.46\cdot 10^5 J

7 0
3 years ago
A 40-cmcm-long tube has a 40-cmcm-long insert that can be pulled in and out. A vibrating tuning fork is held next to the tube. A
Licemer1 [7]

Answer:

1070 Hz

Explanation:

First, I should point out there might be a typo in the question or the question has inconsistent values. If the tube is 40 cm long, standing waves cannot be produced at 42.5 cm and 58.5 cm lengths. I assume the length is more than the value in the question then. Under this assumption, we proceed as below:

The insert in the tube creates a closed pipe with one end open and the other closed. For a closed pipe, the difference between successive resonances is a half wavelength \frac{\lambda}{2}.

Hence, we have

\dfrac{\lambda}{2}=58.5-42.5=16 \text{ cm}

\lambda=32\text{ cm}=0.32 \text{ m}.

The speed of a wave is the product of its wavelength and its frequency.

v=f\lambda

f=\dfrac{v}{\lambda}

f=\dfrac{343}{0.32}=1070 \text{ Hz}

7 0
3 years ago
Methods to reduce the frictional force between the an object and surface which it is in contact.
telo118 [61]
Use of lubricant
Use of ball bearers
Use of streamlined body
Use of graphite
7 0
3 years ago
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