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Andre45 [30]
3 years ago
14

Peak hydraulic systems demands may be met by the use of what ?

Physics
2 answers:
nikklg [1K]3 years ago
8 0
By the use of a Accumulators
Ne4ueva [31]3 years ago
7 0

Answer:

<u><em>The answer is</em></u>: <u>Variable displacement pump.</u>

<u />

Explanation:

The pump <em>increases the hydraulic pressure to the nominal value required by the system. </em>

<u>Variable displacement pump</u>: <em>A variable displacement pump has a fluid outlet that varies to meet the system's pressure demands. The pump output is automatically changed to a compensating pump inside the pump. </em>

Variable displacement pumps are independent of the number of revolutions per minute of the pump as the amount of liquid displaced depends on the needs of the system.

<u><em>The answer is</em></u>: <u>Variable displacement pump.</u>

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What is the magnitude of the force needed to keep a 60 newton rubber block moving across level,dry asphalt in a straight line at
pantera1 [17]

let Coefficients of Friction of Rubber on asphalt (dry) =0.7

F= Coefficients of Friction * normal force = 0.7 * 60 =42 N

so the net force of the rubber is zero, meaning it will travel at a constant speed.

When the rubber is travel at 2m/s, 42N is required to keep moving at constant speed

6 0
3 years ago
Read 2 more answers
Use Newton’s Universal Law of Gravitation to calculate the magnitude of the gravitational force between a 200 kg refrigerator an
expeople1 [14]

Answer:

3.735×10⁻⁶ N

Explanation:

From newton' s law of universal gravitation,

F = Gmm'/r² .............................. Equation 1

Where F = Gravitational force between the person and the refrigerator, m = mass of the person, m' = mass of the refrigerator, r = distance between the person and the refrigerator. G = gravitational universal constant.

Given: m = 70 kg, m' = 200 kg, r = 0.5 m

Constant: G = 6.67×10⁻¹¹ Nm²/kg².

F = (6.67×10⁻¹¹×70×200)/0.5²

F = 93380×10⁻¹¹/0.25

F = 373520×10⁻¹¹

F = 3.735×10⁻⁶ N

Hence the force between the person and the refrigerator =  3.735×10⁻⁶ N

6 0
3 years ago
Glycerin is poured into an open U-shaped tube until the height in both sides is 20 cm. Ethyl alcohol is then poured into one arm
lina2011 [118]

Answer:

Difference in height = 7.5 cm

Explanation:

We are given;.

Height of ethyl alcohol;h2 = 20 cm = 0.2 m

Density of glycerin: ρ1 = 1260 kg/m³

Density of ethyl alcohol; ρ2 = 790 kg/m³

To get the difference in height, the pressure at the top of the open end must be equal to the pressure at the point where the liquids do not mix since both points will be at different levels after the pouring.

Thus;

P1 = P2

Formula for pressure is; P = ρgh

Thus;

ρ1 × g × h1 = ρ2 × g × h2

g will cancel out to give;

ρ1 × h1 = ρ2× h2

Making h1 the subject, we have;

h1 = (ρ2× h2)/ρ1

h1 = (790 × 0.2)/1260

h1 = 0.125 m

Difference in height will be;

Δh = h2 - h1

Δh = 0.2 - 0.125

Δh = 0.075 m = 7.5 cm

4 0
3 years ago
A large volume of the solar system's space is occupied by what?
Dovator [93]
Junk from our atmosphere
3 0
3 years ago
Mike rides his horse with a constant speed of 20 km/h. How far can he travel in 4 hours?
gizmo_the_mogwai [7]

Answer:

Mike can travel 80 Km in 4 hours

4 0
2 years ago
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