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miv72 [106K]
3 years ago
10

The first method of determining the chemical composition of substances in space was to _____.

Chemistry
1 answer:
Art [367]3 years ago
5 0

Answer:The first method to determine the chemical composition of a substance in space was using light. By determining red shift in the observed spectrum of light they could determine the elements they were observing

Explanation:

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A 25.0-mL sample of 0.150 M hydrocyanic acid is titrated with a 0.150 M NaOH solution. The Ka of hydrocyanic acid is 4.9 × 10-10
lara [203]

Answer:

The pOH = 1.83

Explanation:

Step 1: Data given

volume of the sample = 25.0 mL

Molarity of hydrocyanic acid = 0.150 M

Molarity of NaOH = 0.150 M

Ka of hydrocyanic acid = 4.9 * 10^-10

Step 2: The balanced equation

HCN + NaOH → NaCN + H2O

Step 3: Calculate the number of moles hydrocyanic acid (HCN)

Moles HCN = molarity * volume

Moles HCN = 0.150 M * 0.0250 L

Moles HCN = 0.00375 moles

Step 3: Calculate moles NaOH

Moles NaOH = 0.150 M * 0.0305 L

Moles NaOH = 0.004575 moles

Step 4: Calculate the limiting reactant

0.00375 moles HCN will react with 0.004575 moles NaOH

HCN is the limiting reactant. It will completely be reacted. There will react 0.00375 moles NaOH. There will remain 0.004575 - 0.00375 = 0.000825 moles NaOH

Step 5: Calculate molarity of NaOH

Molarity NaOH = moles NaOH / volume

Molarity NaOH = 0.000825 moles / 0.0555 L

Molarity NaOH = 0.0149 M

Step 6: Calculate pOH

pOH = -log [OH-]

pOH = -log (0.0149)

pOH = 1.83

The pOH = 1.83

6 0
3 years ago
Pleaseeeee hellppppp !!!!
Tomtit [17]

Answer:

  1. both
  2. cation
  3. anion
  4. both
  5. cation
  6. anion
  7. both
  8. both
3 0
3 years ago
What is the answer ?
Fantom [35]
The answer is C Does it propaget
4 0
3 years ago
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When cold tempetures are produced in a chemical reaction, the reaction is known as?
Mashutka [201]
Endothermic reaction
8 0
3 years ago
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2.3 moles of CaBr2 contains how many molecules
kkurt [141]

Avogadro's law states that in every mole of a substance, there are 6.022 \times 10^{23} molecules.

This means that in 2.3 moles, there are 2.3(6.022 \times 10^{23})=\boxed{1.4 \times 10^{24} \text{ (to 2 sf)}}

7 0
2 years ago
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