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3 years ago

Hans observed properties of four different waves and recorded observations about each one in his chart.

Physics

2 answers:

bogdanovich [222]3 years ago

8 0

The answer to your question is (Wave W is being diffracted, Wave X is being reflected, and waves Y and Z are being refracted.)

HOPE THIS HELPS YOU CAUSE IM DOING TEST AND I HOPE IM RIGHT AS WELL

PLZ GIVE ME THE BRAINLIEST ANSWER HAVE A GOOD DAY

weeeeeb [17]3 years ago

6 0

The correct answer is Wave W is being diffracted, Wave X is being reflected, and waves Y and Z are being refracted.

Wave X is bouncing off the surface thats why it is being reflected. As the waves pass from one medium to another they change speed i.e. when passing through water into air. This causes waves to bend and change color hence waves X and Z. The scattering of waves through a small opening is called diffraction so wave W

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A circuit contains a 12 volt battery and two 3 ohm bulbs in series. Calculate the current

OLEGan [10]

If there are two bulbs in series, and each bulb has

resistance = 3 ohms,

then their total resistance in series is 6 ohms.

When the series pair of bulbs is connected across the terminals
of the battery, the current through the circuit is

Current = (voltage) / (resistance)

= (12 volts) / (6 ohms) = 2 amperes

5 0

4 years ago

A rod (length = 80 cm) with a rectangular cross section (1.5 mm × 2.0 mm) has a resistance of 0.20 Ω. What is the resistivity of

Andru [333]

Answer:

The resistivity of the material used to make the rod is ρ= 7.5 * 10⁻⁷ Ω.m

Explanation:

R= 0.2 Ω

L= 0.8 m

S= 1.5mm*2mm= 3 mm² = 3 * 10⁻⁶ m²

ρ = (R*S)/L

ρ= 7.5 * 10⁻⁷ Ω.m

7 0

3 years ago

A rocket lifts off the pad at cape canaveral. according to newton's law of gravitation, the force of gravity on the rocket is gi

Alenkinab [10]

The equation is the Law of Universal Gravitation. The gravitational constant G is equal to 6.67×10⁻¹¹ Nm²/kg². The mass of the Earth is <span>5.972 ×10</span>²⁴ kg. Compared to the mass of the Earth, the mass of the rocket is negligible. So, we don't need to know the mass of the rocket. Substituting the values:

F = (6.67×10⁻¹¹ Nm²/kg²)(5.972 ×10²⁴ kg)/(4000 miles*(1.609 km/1mile))²
F = 9616423.08 N

The work is equal to
W = Fd
W = (9616423.08 N)(2000 miles*1.609 km/mile)
W = 9.095×10¹⁰ Joules

8 0

4 years ago

An ion's position vector is initially r with arrow = 7.0i hat â 7.0j + 1.0k, and 5.0 s later it is r with arrow = 7.0i hat + 7.0

harkovskaia [24]

<h2>Answer:</h2>

Shown in the explanation

<h2>Explanation:</h2>

Position vector of a particle at a given instant is given by:

$\vec{r}=x\hat{i}+y\hat{j}+z\hat{k}$

On the other hand, the average velocity is the change in the particle’s position vector divided by time interval:

$\vec{v}=\frac{\Delta \vec{r}}{\Delta t}=\frac{\vec{r_{2}}-\vec{r_{1}} }{t_{2}-t_{1}} \\ \\ \\ Where: \\ \\ \\ \vec{r_{1}}: Initial \ position \\ \\ \vec{r_{2}}: Final \ position \\ \\ t_{1}:Initial \ time \\ \\ t_{2}:Final \ time$

So we have:

$\vec{r_{1}}=7\hat{i}+7\hat{j}+1\hat{k} \\ \\ \vec{r_{2}}=7\hat{i}+7\hat{j}+8\hat{k} \\ \\ \\ Then: \\ \\ \Delta \vec{r} = \vec{r_{2}}-\vec{r_{1}}=7\hat{i}+7\hat{j}+8\hat{k}-(7\hat{i}+7\hat{j}+1\hat{k}) \\ \\ \Delta \vec{r}=7\hat{k} \\ \\ \\ We \ also \ know: \\ \\ \Delta t=5s$

Finally, the average velocity is:

$\vec{v}=\frac{\Delta \vec{r}}{\Delta t} \\ \\ \\ \vec{v}=\frac{7\hat{k}}{5} \\ \\ \boxed{\vec{v}=\frac{7}{5}\hat{k} \ units/s}$

3 0

4 years ago

Two forces act on a 6.00-kg object. One of the forces is 10.0 N. If the object accelerates at 2.00 m/s2

liubo4ka [24]

Given :

Two forces act on a 6.00-kg object. One of the forces is 10.0 N.

Acceleration of object 2 m/s².

To Find :

The greatest possible magnitude of the other force.\

Solution :

Let, other force is f.

So, net force, F = 10 + f.

Now, acceleration is given by :

$a=\dfrac{F}{mass}\\\\a= \dfrac{10+f}{6}\\\\\dfrac{10+f}{6}=2\\\\f = 12 - 10\\\\f = 2 \ N$

Therefore, the greatest possible magnitude of the other force is 2 N.

Hence, this is the required solution.

7 0

3 years ago