Question

A mass m0 is attached to a spring and hung vertically. The mass is raised a short distance in the vertical direction and released. The mass oscillates with a frequency f0 . If the mass is replaced with a mass nine times as large, and the experiment was repeated, what would be the frequency of the oscillations in terms of f0

Answer 1

Answer:

The frequency of the oscillations in terms of fo will be f2=fo/3

E xplanation:

T= $2pie\frac sqrt {m}{k}$

 $\frac {{f2}/times {fo}}$=1:3

⇒f2=fo\3

Here frequency f is inversely poportional to square root of mass m.

so the value of remainder of frequency f2 and fo is equal to 1:3.

⇒$\frac{f2} {f1}$ = $\frac sqrt{m1}[m2}$

⇒$\frac{f2}{fo}$ = 1:3

⇒f2=$\frac{fo} {3}$