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trasher [3.6K]
3 years ago
13

Need help on science please!

Physics
1 answer:
grigory [225]3 years ago
3 0
Fossil fuels are formed when dead, buried, and decomposing organisms are compressed under extreme pressure and heat for millions of years. We need other sources of fuel today... s<span>trictly speaking you don't. But if we hold off developing alternatives until the fossil fuels truly run out, then there will be absolute chaos getting the new ones available. Thats all i got

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Determine the unbalanced force necessary to accelerate a 2.60 kg object at a rate of 14.0 m/s².
slega [8]

Answer:

Explanation:

F = ma

F = 2.60(14.0)

F = 36.4 N

8 0
3 years ago
An object of mass 100kg is moving with a velocity of 5m/s. Calculate the kinetic energy of that object
SOVA2 [1]

Answer:

1250 J

Explanation:

KE = 1/2(100 kg)(5 m/s)^2

KE = 1250 J

8 0
3 years ago
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A 15 kg mass is lifted to a height of 2m. What is gravitational potential energy at this position
7nadin3 [17]

Answer: 294J

Explanation:

U_g=mg(y_f-y_i)

U_g=(15)(9.8)(2-0)=294J

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3 years ago
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A Chevy Camaro drives straight off the top level off a parking garage at 9 m/s. If the car landed 81 meters away from the base o
Tatiana [17]

Answer:

The correct option is c: 396.9 meters.

Explanation:  

First, we need to find the time at which the car landed:

v = \frac{x}{t}

t = \frac{x}{v} = \frac{81 m}{9 m/s} = 9 s                                                                    

Now, we can find the height of the top-level:

y_{f} = y_{0} + v_{0_{y}}t - \frac{1}{2}gt^{2}

Since the car has only a velocity in the horizontal direction, we have:

0 = y_{0} + 0*t - \frac{1}{2}gt^{2}

y_{f} = \frac{1}{2}gt^{2} = \frac{1}{2}9.81 m/s^{2}*(9 s)^{2} = 397 m

Therefore, the correct option is c: 396.9 meters.

I hope it helps you!  

3 0
3 years ago
A weightlifter raises a 200-kg barbell through a height of 2 m in 2.2 s. the average power he develops during the lift is
Lunna [17]
Power is calculated as work per unit time, and work in turn is calculated as force multiplied by distance. In this case, the force required is equivalent to the weight of the barbell multiplied by acceleration due to gravity.
P = W/t = Fd/t = mgd/t = (200 kg)(9.81 m/s^2)(2 m)/2.2 s = 1783.64 Watts.
4 0
4 years ago
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