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Oduvanchick [21]
3 years ago
5

Write two units for electric field intensity and show thier equivalence?​

Physics
2 answers:
nataly862011 [7]3 years ago
7 0

Answer:

Electric field intensity is the force experienced by a test charge q in a electric field E.

emmasim [6.3K]3 years ago
5 0

Answer:

hope it helps...

Explanation:

The SI unit of the electric field is volts per meter (V/m). This unit is equivalent to Newton's per coulomb. These are derived units where Newton is a unit of force and Coulomb is the unit of charge

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15 because i did the math, had this assignment, and also watch a video
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The temperature of a body is from 200 to 300C.The change of temp at absolute scale is
Oliga [24]

Answer:

mark me brainliest

Explanation:

The change of temperature at absolute scale is. A. 3.73 K

7 0
3 years ago
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Consider the video tutorial you just watched. suppose that we repeat the experiment, but this time we replace the original 56-g
Gwar [14]

Answer:

Fm - W = 0    1) true. Imams must separate, to match the two forces, you reach equilibrium

Explanation:

When the magnet is exchanged for a stronger one, but of the same weight, the equilibrium equation

         Fm - W = 0

         Fm = W

If the weight of the imam is the same, the magnetite force must decrease, so that it will occupy the magnets must be separated a greater distance, according to the formula

          Fm = Km m ’m / r²

Where Km is value 10⁻⁷ N s²/C², r is the distance between the poles

Let's review the proposed results

1) true. Imams must separate, to match the two forces, you reach equilibrium

2) False. In this case the weight would be less than the magnetic force

3) False The magnetic force increases and equilibrium is not reached

8 0
3 years ago
Initially (at time t = 0) a particle is moving vertically at 7.5 m/s and horizontally at 0 m/s. Its horizontal acceleration is 1
Lelu [443]

Answer:

t = 0.657 s

Explanation:

given,

initial vertical velocity = 7.5 m/s

initial horizontal velocity = 0 m/s

angle = 49◦

using kinetic equation

final velocity in vertical direction

v sinθ    = u_y   - gt ........................(1)

final velocity in horizontal direction

v cosθ = u_x   + a_x × t

here   u_x = 0.0 m/s

v cosθ = a_x×t ......................(2)

Dividing equation (1) / (2)

tan \theta =\dfrac{u_y - gt}{a_x\times t}

solving for time t

t = \dfrac{u_y}{tan \theta \times a_x + g}

u_y   =   initial velocity along x direction

acceleration along a_x = 1.4 m/s²

g = acceleration due to gravity   = 9.8 m/s²

θ = 43° ,   u_y   =  7.5 m/s    

t = \dfrac{7.5}{tan 49^0\times 1.4+ 9.8}

t = 0.657 s

time taken by the particle is t = 0.657 s

6 0
3 years ago
A 4400 Kg Track Travelling at Intial speed 52m\s can be stopeed in 42 sec. By Gently Break , also the track can be stoped in 7.6
AlladinOne [14]

Answer:

-4,651.42N

Explanation:

Since we are not asked what to find, we can calculate the force applied by the track as shown;

F = ma

F = m(v-u)/t

Substitute the given value

F = 4400(7.6-52)/42

F = 4400(-44.4)/42

F = -4,651.43N

Hence the required force is -4,651.42N

7 0
3 years ago
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