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Oduvanchick [21]
3 years ago
5

Write two units for electric field intensity and show thier equivalence?​

Physics
2 answers:
nataly862011 [7]3 years ago
7 0

Answer:

Electric field intensity is the force experienced by a test charge q in a electric field E.

emmasim [6.3K]3 years ago
5 0

Answer:

hope it helps...

Explanation:

The SI unit of the electric field is volts per meter (V/m). This unit is equivalent to Newton's per coulomb. These are derived units where Newton is a unit of force and Coulomb is the unit of charge

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What is the power of an electric with a current of 0.5 A and a voltage of 120 V ? The formula for power is P =IV
zaharov [31]

Answer:

60Watts

Explanation:

Given parameters:

Current = 0.5A

Voltage  = 120V

Unknown

Power = ?

Solution:

The power in the electric circuit is the product of current and voltage;

      P = IV

Insert the given parameters and solve;

      P = 0.5 x 120

      P  = 60Watts

7 0
3 years ago
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What equation p=m x v used to determine
OverLord2011 [107]

Answer:

The Momentum Calculator uses the formula p=mv, or momentum (p) is equal to mass (m) times velocity (v). The calculator can use any two of the values to calculate the third.

Explanation:

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3 years ago
The masses of the earth and moon are 5.98 x 1024 and 7.35 x 1022 kg, respectively. Identical amounts of charge are placed on eac
dybincka [34]

Answer:

The magnitude of charge on each is 5.707\times 10^{13} C

Solution:

As per the question:

Mass of Earth, M_{E} = 5.98\times 10^{24} kg

Mass of Moon, M_{M} = 7.35\times 10^{22} kg

Now,

The gravitational force of attraction between the earth and the moon, if 'd' be the separation distance between them is:

F_{G} = \frac{GM_{E}M_{M}}{d^{2}}        (1)

Now,

If an identical charge 'Q' be placed on each, then the Electro static repulsive force is given by:

F_{E} = \frac{1}{4\pi\epsilon_{o}}\frac{Q^{2}}{d^{2}}           (2)

Now, when the net gravitational force is zero, the both the gravitational force and electro static force mut be equal:

Equating eqn (1) and (2):

\frac{GM_{E}M_{M}}{d^{2}} = \frac{1}{4\pi\epsilon_{o}}\frac{Q^{2}}{d^{2}}

(6.67\times 10^{- 11})\times (5.98\times 10^{24})\times (7.35\times 10^{22}) = (9\times 10^{9}){Q^{2}}

\sqrt{\farc{(6.67\times 10^{- 11})\times (5.98\times 10^{24})\times (7.35\times 10^{22})}{9\times 10^{9}}} = Q

Q = \pm 5.707\times 10^{13} C

7 0
3 years ago
You can enter compound units that are combinations of other units that are multiplied together.Torque can be calculated by multi
Paraphin [41]

Answer:

3.0 x 10¹ Nm

Explanation:

Torque = F x r

Where F is force applied and r is perpendicular distance from pivot point . r

is also called lever arm

Here F = 15 N and r = 2.0 m

Torque

= 15 N X 2.0 m

= 3.0 10¹ Nm.

4 0
4 years ago
How does the nuclear charge relate to the energy of the 1s orbital?
nlexa [21]

Explanation:

Effective nuclear charge is defined as he net positive charge experienced by an electron in an atom. It is termed "effective" because the shielding effect of electrons prevents higher orbital electrons from experiencing the full nuclear charge of the nucleus due to the repelling effect of inner-layer electrons.

The 1s is the closest shell to the nucleus of an therefore maximum nuclear charge is experienced. The formula for effective nuclear charge is:

Zeff = Z – S

where

Z = the number of protons in the nucleus, and

S = the shielding constant, the average number of electrons between the nucleus and the electron.

Hence, the energy required to remove an electron from the 1s orbital is the strongest.

3 0
4 years ago
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