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mezya [45]
3 years ago
7

How many miles are there if you have 70.5g of Nacl

Chemistry
1 answer:
GenaCL600 [577]3 years ago
4 0
70.5g x 1 mol / 58.5g = 1.2mol of nacl
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How many moles of methane (CH4) could be made from 4.6 moles of hydrogen?
DENIUS [597]

Answer:

Number of moles of methane form = 2.3 mol

Explanation:

Given data:

Number of moles of Hydrogen = 4.6 mol

Number of moles of methane form = ?

Solution:

Chemical equation:

C + 2H₂     →   CH₄

Now we will compare the moles of methane with hydrogen from balance chemical equation.

                     H₂              :           CH₄

                       2              :             1

                     4.6             :            1/2×4.6 = 2.3 mol  

Form 3.6 moles of hydrogen 2.3 moles of methane can be formed.

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Can wind energy be used in transportation
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Yes because the wind energy can power a gas pump, then the gas would go into some form of automobile
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What is the molecular weight of magnesium chloride?​
valentinak56 [21]

Answer:

Magnesium chloride/Molar mass

95.211 g/mol

Explanation:

6 0
3 years ago
What happens when hydrogen reacts with nitrogen at necessary conditions.​
Orlov [11]

Answer:

When hydrogen gas combines with nitrogen to form Ammonia the following chemical reaction will take place. Our equilibrium reaction will be N2(g) + 3H2(g) ⇔ 2NH3(g) + Heat. In this case, Hydrogen and nitrogen react together to form ammonia.

Explanation:

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In an experiment, a student needs 250.0 mL of a 0.100 M copper (II) chloride solution. A stock solution of 2.00 M copper (II) ch
LekaFEV [45]

Answer : The volume of stock solution needed are, 12.5 mL

Explanation :

Formula used :

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the initial molarity and volume of copper (II) chloride.

M_2\text{ and }V_2 are the final molarity and volume of stock solution of copper (II) chloride.

We are given:

M_1=0.100M\\V_1=250.0mL\\M_2=2.00M\\V_2=?

Putting values in above equation, we get:

0.100M\times 250.0mL=2.00M\times V_2\\\\V_2=12.5mL

Hence, the volume of stock solution needed are, 12.5 mL

8 0
3 years ago
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