1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
DochEvi [55]
3 years ago
6

11.A heat engine operates between two reservoirs at 800 and 20°C. One-half of the work output of the heat engine is used to driv

e a Carnot heat pump that removes heat from the cold surroundings at 2°C and transfers it to a house maintained at 22°C. If the house is losing heat at a rate of 62,000 kJ/h, determine the minimum rate of the heat supply to the heat engine required to keep the house at 22°C.
Engineering
1 answer:
statuscvo [17]3 years ago
3 0

Answer: Meh account banned

Explanation:

You might be interested in
In Lab 7, we worked through a program that displayed the homeless shelter occupancy over time. The same approach can be used for
Bezzdna [24]

Answer:

Explanation:

The python code to generate this is quite simple to run.

i hope you understand everything written here, you can as well try out other problems to understand better.

First to begin, we import the package;

Code:

import pandas as pd

import matplotlib.pyplot as plt

name = input('Enter name of the file: ')

op = input('Enter name of output file: ')

df = pd.read_csv(name)

df['Date'] = pd.to_datetime(df["Date"].apply(str))

plt.plot(df['Date'],df['Absent']/(df['Present']+df['Absent']+df['Released']),label="% Absent")

plt.legend(loc="upper right")

plt.xticks(rotation=20)

plt.savefig(op)

plt.show()

This should generate the data(plot) as seen in the uploaded screenshot.

thanks i hope this helps!!!

6 0
3 years ago
Find R subscript C and R subscript B in the following circuit such that BJT would be in the active region with V subscript C E e
Alex777 [14]

Answer: Rc = 400 Ω and Rb = 57.2 kΩ

Explanation:

Given that;

VCE = 5V

VCC = 15 V

iC = 25 mA

β = 100

VD₀ = 0.7 V

taking a look at the image; at loop 1

-VCC + (i × Rc) + VCE = 0

we substitute

-15 + ( 25 × Rc) + 5 = 0

25Rc = 10

Rc = 10 / 25

Rc = 0.4 k

Rc = 0.4 × 1000

Rc = 400 Ω

iC = βib

25mA = 100(ib)

ib = 25 mA / 100

ib = 0.25 mA

ib = 0.25 × 1000

ib = 250 μAmp

Now at Loop 2

-Vcc + (ib×Rb) + VD₀ = 0

-15 (250 × Rb) + 0.7 = 0

250Rb = 15 - 0.7

250Rb = 14.3

Rb = 14.3 / 250

Rb = 0.0572 μ

Rb = 0.0572 × 1000

Rb = 57.2 kΩ

Therefore Rc = 400 Ω and Rb = 57.2 kΩ

8 0
3 years ago
Air is pumped from a vacuum chamber until the pressure drops to 3 torr. If the air temperature at the end of the pumping process
malfutka [58]

Answer:

The final pressure is 3.16 torr

Solution:

As per the question:

The reduced pressure after drop in it, P' = 3 torr = 3\times 0.133\ kPa

At the end of pumping, temperature of air, T = 5^{\circ}C = 278 K

After the rise in the air temperature, T' = 20^{\circ}C = 293 K

Now, we know the ideal gas eqn:

PV = mRT

So

P = \frac{m}{V}RT

P = \rho_{a}RT          (1)

where

P = Pressure

V = Volume

\rho_{a} = air\ density

R = Rydberg's constant

T = Temperature

Using eqn (1):

P = \rho_{a}RT

\rho_{a} = \frac{P}{RT}

\rho_{a} = \frac{3 times 0.133\times 10^{3}}{0.287\times 278} = 0.005 kg/m^{3}

Now, at constant volume the final pressure, P' is given by:

\frac{P}{T} = \frac{P'}{T'}

P' = \frac{P}{T}\times T'

P' = \frac{3}{278}\times 293 = 3.16 torr

7 0
4 years ago
Refrigerant 134a enters the evaporator of a refrigeration system operating at steady state at -16oC and a quality of 20% at a ve
Dmitry [639]

Answer:

mass flow rate = 0.0534 kg/sec

velocity at exit = 29.34 m/sec

Explanation:

From the information given:

Inlet:

Temperature T_1 = -16^0\ C

Quality x_1 = 0.2

Outlet:

Temperature T_2 = -16^0 C

Quality  x_2 = 1

The following data were obtained at saturation properties of R134a at the temperature of -16° C

v_f= 0.7428 \times 10^{-3} \ m^3/kg \\ \\  v_g = 0.1247 \ m^3 /kg

v_1 = v_f + x_1 ( vg - ( v_f)) \\ \\ v_1 = 0.7428 \times 10^{-3} + 0.2 (0.1247 -(0.7428 \times 10^{-3})) \\ \\  v_1 = 0.0255 \ m^3/kg \\ \\ \\  v_2 = v_g = 0.1247 \ m^3/kg

m = \rho_1A_1v_1 = \rho_2A_2v_2 \\ \\  m = \dfrac{1}{0.0255} \times \dfrac{\pi}{4}\times (1.7 \times 10^{-2})^2\times 6  \\ \\ \mathbf{m = 0.0534 \ kg/sec}

\rho_1A_1v_1 = \rho_2A_2v_2 \\ \\ A_1 =A_2  \\ \\  \rho_1v_1 = \rho_2v_2   \\ \\ \implies \dfrac{1}{0.0255} \times6 = \dfrac{1}{0.1247}\times (v_2)\\ \\ \\\mathbf{\\ v_2 = 29.34 \ m/sec}

3 0
3 years ago
Compare and contrast an electric vehicle with one powered by a fuel cell.
zmey [24]

Answer:

both technologies offer a cleaner alternative to internal combustion engines, and both use electric motors powered by electrochemical device.

3 0
3 years ago
Other questions:
  • Write down a transfer function of a stable system for which pure proportional feedback could drive the system unstable.
    11·1 answer
  • Air is contained in a vertical piston–cylinder assembly such that the piston is in static equilibrium. The atmosphere exerts a p
    9·1 answer
  • 4. Which of the following drive roll designs is used
    8·1 answer
  • A light train made up of two cars is traveling at 90 km/h when the brakes are applied to both cars. Know that car A has a mass o
    8·1 answer
  • What conclusions can you reach from your gym teacher’s science-fair display?
    13·1 answer
  • Can somebody help me
    9·1 answer
  • A compound cylinder is formed by shrinking a tube of 250 mm internal diameter and 25 mm wall thickness onto another tube of 250
    12·1 answer
  • B) Calculate the FS against uplift and calculate effoctive stress at the base level for water
    11·1 answer
  • Calculate the number of vacancies per cubic meter for some metal, M, at 783°C. The energy for vacancy formation is 0.95 eV/atom,
    11·1 answer
  • What’s the answer???
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!