Answer:
A 2 N force pulling and a 10 N force pulling left while a 12N force pulls right.
Explanation:
It is given that,
Initial velocity of the car, u = 14 m/s
Final velocity of the car, v = 21 m/s
Time taken, t = 6 s
Acceleration of the car is equal to the change in speed divided by time i.e. it can be written as :

a = 1.166 m/s²
or
a = 1.17 m/s²
For finding how fat it travel in this time is calculated using third equation of motion :

s = distance


s = 104.7 m
Hence, the acceleration of the car is 1.166 m/s² and distance covered by it is 104.7 m
Explanation:
If two particles are involved in an elastic collision, the velocity of the second particle after collision can be expressed as: v2f=2⋅m1(m2+m1)v1i+(m2−m1)(m2+m1)v2i v 2 f = 2 ⋅ m 1 ( m 2 + m 1 ) v 1 i + ( m 2 − m 1 ) ( m 2 + m 1 ) v 2 i .