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Brilliant_brown [7]
3 years ago
11

How is sodium peroxide formed?​

Chemistry
1 answer:
nordsb [41]3 years ago
8 0

Answer:

Sodium peroxide can be prepared on a large scale by the reaction of metallicsodium with oxygen at 130–200 °C, a process that generates sodium oxide, which in a separate stage absorbs oxygen: 4 Na + O2 → 2 Na2O. The ozone oxidizes the sodium to form sodium peroxide.

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faltersainse [42]

Answer: Hope this helps

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6 0
3 years ago
Modify the given fatty acid so that it represents the 18‑carbon fatty acid designated 18:2(Δ9,12). Draw any double bonds in the
Mekhanik [1.2K]

Answer:

See explanation

Explanation:

In this case, we have to remember the meaning of the nomenclature "18:2Δ9,12".  Where 18 is the <u>number of carbon atom</u>s, 2 is the <u>number of double bonds,</u> and the numbers successive to Δ "delta" the position of the double bonds <u>starting</u> to count from the carboxylic -COOH end of the molecule.

In other words, the main functional group is a <u>carboxylic acid</u>. We have a total of 18 carbons. Additionally, we have 2 double bonds. On carbons 9 and 12.

Lets see figure 1

I hope it helps!

5 0
3 years ago
All of the following show a periodic pattern except
AlekseyPX
<span>A. the dog ate everyone of his play toys</span>
4 0
2 years ago
Calculate the mass of calcium chloride that contains 3.20 x 1024 atoms of chlorine.
frez [133]

Answer:

294.87 gm  CaCl_2

Explanation:

The computation of the  mass of calcium chloride is shown below:

But before that following calculations need to be done

Number of moles of chlorine atom is

= 3.20 × 10^24 ÷ 6.022 × 10^23

= 5.314 moles

As we know that

1 mole CaCl_2 have the 2 moles of chlorine atoms

Now 5.341 mole chloride atoms would be

= 1 ÷ 2 × 5.314

= 2.657 moles

Now

Mass of CaCl_2 = Number of moles × molar mass of  CaCl_2

= 2.657 moles × 110.98 g/mol

= 294.87 gm  CaCl_2

7 0
3 years ago
The diagram above shows the repeating groups of atoms that make up two samples. Will the
Tcecarenko [31]
Yes it’s d yes yes yes
8 0
2 years ago
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