Answer:
(A) Distance will be equal to 1.75 km
(B) Displacement will be equal to 1.114 km
Explanation:
We have given circumference of the circular track = 3.5 km
Circumference is given by 
r = 0.557 km
(a) It is given that car travels from southernmost point to the northernmost point.
For this car have to travel the distance equal to semi perimeter of the circular track
So distance will be equal to 
(b) If car go along the diameter of the circular track then it will also go from southernmost point to the northernmost point. and it will be equal to diameter of the track
So displacement will be equal to d = 2×0.557 = 1.114 m
Answer:
The appropriate solution is "2.78 mm".
Explanation:
Given:

or,



or,

As we know,
Fringe width is:
⇒ 
hence,
Separation between second and third bright fringes will be:
⇒ 


or,

Answer:
Part a)

Part b)

Explanation:
Time period of sun is given as



Now the radius of the orbit of sun is given as



Part a)
centripetal acceleration is given as




Part b)
orbital speed is given as



Given :
Number of operations move through a pocket calculator during a full day's operation ,
.
To Find :
How many coulombs of charge moved through it .
Solution :
We know , charge in one electron is :

So , charge on n electron is :

Therefore , -21.44 coulombs of charge is moved through it .
Hence , this is the required solution .