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inn [45]
4 years ago
6

I need help how do you do this ?

Chemistry
1 answer:
Karolina [17]4 years ago
7 0
Sorry, haven't came across that as of yet.
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Fe(s) + CuSO4(aq) <===> Cu(s) + FeSO4(aq)
Ludmilka [50]

Answer : The original concentration of copper (II) sulfate in the sample is, 5.6\times 10^{-1}g/L

Explanation :

Molar mass of Cu = 63.5 g/mol

First we have to calculate the number of moles of Cu.

Number of moles of Cu = \frac{\text{Mass of Cu}}{\text{Molar mass of Cu}}=\frac{89\times 10^{-3}g}{63.5g/mol}=1.40\times 10^{-3}mole

Now we have to calculate the number of moles of CuSO_4

Number of moles of Cu = Number of moles of CuSO_4

Number of moles of CuSO_4 = 1.40\times 10^{-3}mole

Now we have to calculate the molarity of CuSO_4

\text{Molarity}=\frac{\text{Moles of }CuSO_4\times 1000}{\text{Volume of solution (in mL)}}

Now put all the given values in this formula, we get:

\text{Molarity}=\frac{1.40\times 10^{-3}mole\times 1000}{400.mL}=0.0035M

To change mol/L into g/L, we need to multiply it with molar mass of CuSO_4

Molar mass of CuSO_4= 159.609 g/mL

Concentration in g/L = 0.0035M\times 159.609g/mol=0.5586g/L\approx 5.6\times 10^{-1}g/L

Thus, the original concentration of copper (II) sulfate in the sample is, 5.6\times 10^{-1}g/L

3 0
3 years ago
Write the balanced equation for the neutralization reaction between h2so4 and koh
Dafna11 [192]
H2SO4 + 2KOH ---> K2SO4 + 2H2O
:)
8 0
4 years ago
PLEASE HELP ITS VERY EASY FOR OTHER PLEASE ITS A TEST DUE IN AN HOUR PLEASEEEEEEEEEE
jonny [76]

Answer:

10 N

Explanation:

6 0
4 years ago
Read 2 more answers
Please help me with these?
Julli [10]

Question 5 is the second one.


8 0
3 years ago
Which section of a lab report would most appropriately contain the possible sources of error in an experiment?
Vlad1618 [11]

The lab report contains the theory, process, data and calculation of the experiment. The theory and process are remains fixed for a particular experiment. Thus there is no chance to get error from these two part. The calculation depends upon the reading or data of the experiment. The calculation is also unique and based on the data. Thus the error come from the data of the experiment. As for example for a titration experiment the data recorded in the process from the burret is the source of error, on which the calculation depends.    

7 0
4 years ago
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