The answer to this question would be the second option or B (The moon's orbit is closer to Earth.) because there are multiple different high tides that are caused by either the moon being unusually close to the Earth or the moon is at it's Quarterly or New Moon phases.
Hope that this helped you! :D
<u>Answer:</u> The molarity of calcium hydroxide in the solution is 0.1 M
<u>Explanation:</u>
To calculate the concentration of base, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is
are the n-factor, molarity and volume of base which is
We are given:
Putting values in above equation, we get:
Hence, the molarity of in the solution is 0.1 M.
Answer:
10
Explanation:
The unbalanced combustion reaction is shown below as:-
On the left hand side,
There are 3 hydrogen atoms and 1 nitrogen atom and 2 oxygen atoms
On the right hand side,
There are 1 nitrogen atom and 2 hydrogen atoms and 2 oxygen atoms
Thus,
Right side, must be multiplied by 6 to balance hydrogen.
Left side, must be multiplied by 4 to balance hydrogen.
Also, Right side, is multiplied by 4 so to balance nitrogen.
Left side, must be multiplied by 5 to balance the whole reaction.
Thus, the balanced reaction is:-
Sum of Coefficient of product - 4 + 6 = 10
Answer:
Equation S= (°C + 117.3)/1.956 °S(25°C) = 72.25°S
Explanation:
To know the difference between the scales, we must initially know the length of our new scale compared to the scale in Celcius degrees, for this we add the absolute value of our melting point and the boiling point | -117.3 ° C | + | 78.3 ° C | = 195.6 ° C
Because our new scale will be divided into 100 equal parts we can know the unit value of each degree ° C concerning degrees ° S. 195.6 / 100 = 1,956 ° C / ° S
For a linear relationship of the scales, the crossing point at ° S = 0.00 is equal to -117.3 ° C. whereby we can clear our equation to know the temperature in degrees Celcius from ° S
°C= -117.3 + °S * 1.956°C/°S
Clearing °S we obtain
°S = (°C + 117.3)/1.956°C/°S
(ii)
In this new scale the temperature of 25°C will be readed as
°S = (25°C+117.3)/1.956°C/°S = 72.25°S
For a) [Ru(NH₃)₅Cl]SO₄
Ru configuration = d⁶s²
In this complex Ru oxidation number is +3
Ru³⁺ configuration = d⁵
number of
electrons = 5
For b) Na₂[Os(CN)₆]
Os configuration = d⁶s²
In this complex Os oxidation number is +4
Os⁴⁺ configuration = d⁴
number of
electrons = 4