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melamori03 [73]
2 years ago
6

A mass of 8kg is suspended from a spring with a spring constant of 16N/m and then released, creating periodic motion. At what di

stance below the natural length of the spring will the mass finally come to rest?
a. 4.9m
b. 9.8m
c. 19.6m
d. 7.2m
Physics
1 answer:
umka21 [38]2 years ago
7 0

The spring will come to rest 4.9 m below the natural length

Explanation:

The mass-spring system will come to rest when the restoring force on the spring (pulling upward) balances the weight of the mass (pulling downward). Mathematically, this can be written as

F_x = W\\kx = mg

where

k is the spring constant

x is the elongation of the spring

m is the mass

g is the acceleration of gravity

In this problem, we have:

m = 8 kg is the mass

g=9.8 m/s^2 is the acceleration of gravity

k=16 N/m is the spring constant

Solving the equation for x,

x=\frac{(8)(9.8)}{16}=4.9 m

Therefore, the spring will come to rest 4.9 m below the natural length.

Learn more about forces:

brainly.com/question/8459017

brainly.com/question/11292757

brainly.com/question/12978926

#LearnwithBrainly

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Explanation:

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Hence the average induced emf is:

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I hope it helps you!

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3 years ago
Liam throws a water balloon horizontally at 8.2 m/s out of a window 18 m from the ground.
Alecsey [184]

Time taken by the water balloon to reach the bottom will be given as

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now by the above formula

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18 = 4.9 t^2

t = 1.92 s

now in the same time interval we can say the distance moved by it will be

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A speed skater moving across frictionless ice at 8.4 m/s hits a 5.7 m -wide patch of rough ice. She slows steadily, then continu
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Answer:

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Explanation:

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8 0
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