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Debora [2.8K]
3 years ago
11

What is a vernier caliper used for?​

Physics
1 answer:
iris [78.8K]3 years ago
5 0

me ajudem por favor pra agora de noite

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If a car changes its velocity from 32km/hr in 8.0 seconds what is its acceleration
puteri [66]

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A 1.50 µF capacitor and a 3.50 µF capacitor are connected in series across a 2.50 V battery. How much charge (in µC) is stored o
Nataly_w [17]

Explanation:

The given data is as follows.

      C_{1} = 1.50 \times 10^{-6} F

      C_{1} = 3.50 \times 10^{-6} F    

      Voltage = 2.50 V

Hence, calculate the equivalence capacitor as follows.

    \frac{1}{C} = \frac{1}{C_{1}} + \frac{1}{C_{2}}

    \frac{1}{C} = \frac{1}{1.50 \times 10^{-6} F} + \frac{1}{3.50 \times 10^{-6} F}

                 = 0.945 \times 10^{-6} F

          C = 1.06 \times 10^{-6} F

Now, we will calculate the charge across each capacitance as follows.

              Q = CV

                  = 1.06 \times 10^{-6} F \times 2.50 V

                  = 2.65 \times 10^{-6} C

                  = 2.65 \mu C

Thus, we can conclude that 2.65 \mu C is the charge stored on each given capacitor.

5 0
3 years ago
While vacationing in the mountains you do some hiking. In the morning, your displacement is S⃗ morning= (2200 m , east) + (4000
Minchanka [31]

Answer:

a

    The hiker (you ) is  200 m below his/her(your) starting point

b

   The resultant displacement in the north east direction is

a  = 6562.0 \  m

    The resultant displacement in vertical direction (i.e the altitude change )

  b =6503.1 \  m

Explanation:

From the question we are told that  

  The displacement in the morning is  S_{morning} =  (2200 \m , east) + (4000\ m\ north) + (100 \ m ,\ vertical)

   The displacement in the afternoon is  S _{afternoon}= (1300\ m ,\ west) + (2500 \ m ,\ north) - (300\ m ,\ vertical)

Generally the direction west is negative , the direction east is positive

                 the direction south is negative , the direction north is  positive

resultant displacement  is mathematically evaluated as  

    (2200 \m , east) +( - 1300\ m ,\ west) = 900 \ m \ east

     (4000\ m\ north)  + (2500 \ m ,\ north) = 6500  \ m ,\ north

     (100 \ m ,\ vertical) - (300\ m ,\ vertical) = -200 \ m

From the above calculation we see that at the end of the hiking the hiker (you) is  200 m below his/her(your) initial position

Generally from Pythagoras theorem , the resultant displacement in the north east direction is

      a  =  \sqrt{900^2 + 6500^2}

=>     a  = 6562.0 \  m

Generally from Pythagoras theorem , the resultant displacement in vertical direction (i.e the altitude change )

      b = \sqrt{6500^2 +(-200)^2  }

=>   b =6503.1 \  m

   

5 0
3 years ago
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