Answer:
1. They will react.
2. 2HCI + Zn —> ZnCl2 + H2
Explanation:
1. From the question given above,
We can see that Zn is higher than H in the activity series.
NOTE: Elements higher (i.e at the top) in the activity series will displace those lower (i.e at the bottom) in the series. Thus, Zn is higher in the series than H. Therefore, Zn will displace H from solution. Hence, they will react.
2. The product obtained from the reaction can be seen as follow:
HCI + Zn —> ZnCl2 + H2
The above equation can be balance as follow:
There are 2 atoms of H on the right side and 1 atom on the left side. It can be balance by putting 2 in front of HCl as shown below:
2HCI + Zn —> ZnCl2 + H2
The effects<span> of A</span>nthrax<span> on the </span>body<span> include, shock, difficulty breathing, and intestinal inflammation. In serious cases, A</span>nthrax<span> can lead to inflammation of the areas surrounding the brain, and spinal cord, causing severe bleeding. This illness could also lead to death.
I hope this helps!</span>
<h3>
Answer:</h3>
4649.16 g
<h3>
Explanation:</h3>
We are given;
- The equation for the reaction
2C₄H₁₀ + 13O₂→ 8CO₂ + 10H₂O
We are required to determine the mass of water produced.
<h3>
Step: Determine the number of moles of C₄H₁₀</h3>
We know that, moles = Mass ÷ Molar mass
Molar mass of C₄H₁₀ is 58.14 g/mol
Therefore;
Moles of C₄H₁₀ = 3000 g ÷ 58.14 g/mol
= 51.5996
= 51.60 moles
<h3>Step 2: Determine the number of moles of water </h3>
- From the equation, 2 moles of C₄H₁₀ reacts to produce 10 moles of water
Therefore;
Moles of water = Moles of C₄H₁₀ × 10/2
= 51.60 moles × 5
= 258 moles
<h3>Step 3: Determine the mass of water produced </h3>
We know that; mass = moles × molar mass
Molar mass of water = 18.02 g/mol
Thus;
Mass of water = 258 moles × 18.02 g/mol
= 4649.16 g
Therefore, the mass of water produced will be 4649.16 g
Hi there,
Your answere would be "when you draw conclusions"
This is because you talk about your hypothesis and what supports it at the end of an experiment.
Hope this helps!
The structure that helps these organisms in hypotonic environments is the contractile vacuole.
As water enters the cell from the less-solute environment, the cell would normally burst; however, the contractile vacuole takes up this water and pumps it back out of the cell.