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2 years ago

Z is a covalent substance. In an experiment, a sample of pure solid Z was continually heated for 11 minutes

1 answer:

6 0

When a pure solid Z sample it a covalent compound is heated continually for 11 minutes it will undergo disintegration leaving the bonds intact.

<h3>What is a covalent compound?</h3>

A covalent compound is a compound that is made up of molecules which share one or more pairs of valence electrons and are bonded together by a covalent bond.

One of the major factors that affect compounds with covalent bonds is temperature.

The increase in temperature during heating leads to the separation of the atoms from each other but leaving the bonds intact.

Learn more about covalent bonds here:

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Vikentia [17]

Answer:

Mantle

Explanation:

Convection currents in the Earth occur in the mantle. The core of the Earth is extremely hot, and material in the mantle close to the core is heated...

Hope that help <3

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3 years ago

What is the name of the process that plants use to remove carbon from the atmosphere

Studentka2010 [4]

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3 years ago

Which of the following is a type of electromagnetic radiation?

emmasim [6.3K]

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3 years ago

Read 2 more answers

Instead of using ratios for back titrations we can also use molarities, if our solutions are standardized. A 0.196 g sample of a

kvv77 [185]

Answer:

The mass percent of Al(OH)₃ is 15.3%

Explanation:

The reaction is:

Al(OH)₃ + 3HCl = AlCl₃ + 3H₂O

The excess acid is neutralized with a solution of sodium hidroxide, in the reaction:

NaOH + HCl = NaCl + H₂O

The total moles of HCl is:

$n_{HCl,total} =M_{HCl} *V_{HCl} =0.111*0.025=2.78x10^{-3} moles$

From the second titration, the moles of excess of HCl is:

$n_{HCl,excess} =n_{NaOH} =M_{NaOH} *V_{NaOH} =0.132*0.01105=1.46x10^{-3} moles$

The difference between the total and excess of HCl, it can be know the moles that reacts with the aluminum hydroxide, is:

$n_{HCl,reacts} =n_{HCl,total}-n_{HCl,excess} =2.78x10^{-3} moles-1.46x10^{-3} moles=1.32x10^{-3} moles$

The ratio between HCl and Al(OH)₃ is 3:1. The MW for aluminum hydroxide is 78 g/mol, thus:

$m_{Al(OH)3} =1.32x10^{-3} molesHCl*\frac{1molAl(OH)3}{3molesHCl} *\frac{78gAl(OH)3}{1molAl(OH)3} =0.03g$

The percentage of Al(OH)₃ is:

$Percentage-Al(OH)3=\frac{m_{Al(OH)3} }{m_{antiacid} } *100=\frac{0.03}{0.196} =15.3$ %

3 0

3 years ago

How can we calculate empirical formula

Serggg [28]

Explanation:

TO calculate emperical formula , we need percentage composition of the elements and molecular mass of a specific compound which is already given in the question

then create a table with 1.name of element, 2.percentage given and its atomic mass , 3.no. of moles

( %given/at.mass of element) ... then take the least value in the no. of moles you have found now and divide with each no. of moles value .. to get a simple digit number.

You have got the empirical formula

7 0

3 years ago