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NemiM [27]
3 years ago
12

What is the volume of a sample of liquid mercury that has a mass of 53.8 g, given that the density of mercury is 13.6 g/mL? Answ

er in units of mL.
Chemistry
1 answer:
Liula [17]3 years ago
6 0

The formula for density is:

density=\frac{mass}{volume}

We know the density for mercury is 13.6 g/mL, and we know the mass of the sample is 53.8 g. Thus, we can plug these numbers into our equation and solve for volume.

The volume is unknown, so we can simply denote it as "x"

13.6 g/mL=\frac{53.8 g}{x}

multiply both sides by x

(x)(13.6 g/mL)=\frac{53.8 g}{x}(x)

The x's cancel out on the right side and you are left with

(x)(13.6 g/mL)=53.8 g

From here, simply divide both sides of the equation by 13.6 g/mL and solve for x.

\frac{(x)13.6 g/mL}{13.6 g/mL}=\frac{53.8 g}{13.6 g/mL}

x=3.955882353 mL

Round to 3 significant figures, and your final answer is:

x=3.96 mL

The volume of the sample of mercury was 3.96 mL.


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Answer:

T₂ = 150 K

Explanation:

Given data:

Initial volume = 4 L

Initial temperature = 300 K

Final volume = 2 L

Final temperature = ?

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

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Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₂ = T₁V₂/V₁  

T₂ = 300 K × 2L / 4 L

T₂ = 600 L.K / 4 L

T₂ = 150 K

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If kc = 7.04 × 10-2 for the reaction: 2 hbr(g) ⇌h2(g) + br2(g), what is the value of kc for the reaction: 1/2 h2(g) + 1/2 br2 ⇌h
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At the first reaction when 2HBr(g) ⇄ H2(g) + Br2(g)
So Kc = [H2] [Br2] / [HBr]^2
7.04X10^-2 = [H2][Br] / [HBr]^2

at the second reaction when 1/2 H2(g) + 1/2 Br2 (g) ⇄ HBr
Its Kc value will = [HBr] / [H2]^1/2*[Br2]^1/2
we will make the first formula of Kc upside down:
1/7.04X10^-2 = [HBr]^2/[H2][Br2]
and by taking the square root: 
∴ √(1/7.04X10^-2)= [HBr] / [H2]^1/2*[Br]^1/2
∴ Kc for the second reaction = √(1/7.04X10^-2) = 3.769 
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