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4 years ago

Sorry about last time sorry the question is

Physics

1 answer:

Ivanshal [37]4 years ago

8 0

Explanation:

It will increase as according to the Newton gravitational law the force of attraction is directly proportional to the product of the masses and inversely proportional to the square of the distance separating them

In case of atoms it will increase the decrease

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How many kilometers are in 1.40 miles

ELEN [110]

The answer is 2.25308 km

4 0

3 years ago

A series circuit has a capacitor of 0.25 × 10⁻⁶ F, a resistor of 5 × 10³ Ω, and an inductor of 1H. The initial charge on the cap

viktelen [127]

Answer:

$q = (3 + e^{-4000 t} - 4 e^{-1000 t})\times 10^{-6}$

at t = 0.001 we have

$q = 1.55 \times 10^{-6} C$

at t = 0.01

$q = 2.99 \times 10^{-6} C$

at t = infinity

$q = 3 \times 10^{-6} C$

Explanation:

As we know that they are in series so the voltage across all three will be sum of all individual voltages

so it is given as

$V_r + V_L + V_c = V_{net}$

now we will have

$iR + L\frac{di}{dt} + \frac{q}{C} = 12 V$

now we have

$1\frac{d^2q}{dt^2} + (5 \times 10^3) \frac{dq}{dt} + \frac{q}{0.25 \times 10^{-6}} = 12$

So we will have

$q = 3\times 10^{-6} + c_1 e^{-4000 t} + c_2 e^{-1000 t}$

at t = 0 we have

q = 0

$0 = 3\times 10^{-6} + c_1 + c_2$

also we know that

at t = 0 i = 0

$0 = -4000 c_1 - 1000c_2$

$c_2 = -4c_1$

$c_1 = 1 \times 10^{-6}$

$c_2 = -4 \times 10^{-6}$

so we have

$q = (3 + e^{-4000 t} - 4 e^{-1000 t})\times 10^{-6}$

at t = 0.001 we have

$q = 1.55 \times 10^{-6} C$

at t = 0.01

$q = 2.99 \times 10^{-6} C$

at t = infinity

$q = 3 \times 10^{-6} C$

5 0

3 years ago

You go to an amusement park with your friend Betty, who wants to ride the 70-m-diameter Ferris wheel. She starts the ride at the

Ksenya-84 [330]

Answer:

Part a)

$d = 23.94 m$

Part b)

$\theta = 110 degree$

Explanation:

Part a)

As we know that initially the position vector is r

then the same magnitude position vector is rotated by 40 degree angle

so displacement magnitude is the magnitude of change in position vector

so it is given as

$d = \sqrt{r_1^2 + r_2^2 + 2r_1r_2cos(180-\theta)}$

$r_1 = r_2 = 35 m$

$d = \sqrt{35^2 + 35^2 -2(35)(35)cos40}$

$d = 23.94 m$

Part b)

now we need to find the direction of the displacement vector

so let say it makes an angle with x axis so we have

$tan\theta = \frac{rsin\phi}{r - rcos\phi}$

$tan\theta = \frac{sin 40}{1 - cos40}$

$\theta = 110 degree$

4 0

3 years ago

Which body is found inside the solar system?

Digiron [165]

Moon! because it is the only one in the solar system:)

6 0

2 years ago

Which medium below conducts sound the fastest?

kumpel [21]

Which medium below conducts sound the fastest?

A. a wall

<u>B. Steel </u>

C. Plastic

D. Cardboard

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3 years ago

Read 2 more answers