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Alexandra [31]
3 years ago
5

What mass of water can be obtained from 4.0 g of H2 and 16 g of O2?

Chemistry
1 answer:
rusak2 [61]3 years ago
4 0

Answer:

18 grams of water, will be produced from 4 g of H₂ and 16g of O₂

Explanation:

Reaction: 2H₂ + O₂  ⇒  2H₂O

Moles = Mass / Molar mass

Molar mass H₂ = 2g/m

Molar mass O₂ = 32 g/m

4g /2g/m = 2moles

16g / 32 g/m = 0.5 moles

Ratio is 2:1

For 2 moles of hydrogen, I need 1 mol of oxygen; I have 2 moles of H₂, but I only have 0.5 of O₂, so the O₂ is the limiting reagent.

1 mol of O₂ produces 2 mol of water

0.5 moles of O₂ will produce, the double → 1 mol of water.

Molar mass of water is 18 g/m

1 mol . 18 g/m = 18 g

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At what temperature is the following reaction at equilibrium? 2Na, O, + 2H,0 + 4NaOH + O, AH° = -109 kJ, ASO = -133.2 J/K
natali 33 [55]

Answer:

Temperature = 818 K

Explanation:

The given reaction is:

2Na2O2 + H2O \rightarrow 4NaOH + O2

The change in enthalpy is: ΔH°= -109 kJ

The change in entropy is : ΔS° = -133.2 J/k = -0.1332 kJ/K

Based on the Gibbs-Helmholtz equation the standard free energy change is given as:

\Delta G^{0}=\Delta H^{0}-T\Delta S^{0}

At equilibrium ΔG° = 0. therefore:

\Delta H^{0} = T\Delta S^{0}

T=\frac{\Delta H^{0}}{\Delta S^{0}}=\frac{-109}{-0.1332}=818 K

4 0
3 years ago
In the formula
faust18 [17]

Answer: remove a H2 molecule from the left side of the equation

Explanation:

6 0
3 years ago
Two of the seven different pea traits examined by Mendel involved genes that we now know are linked. Knowing this, can you expla
ser-zykov [4K]

Answer:: Mendel studied how traits are been passed from parents to offspring using seven features in peas, including height, flower color, seed color, and seed shape. To do this he divided the pea plant into short height and tall height. From this experiment he proposed a principle called independent assortment, which describes how different genes independently separate from one another when reproductive cells develop. Though this experiment was studied using gene formation in prokaryotic cell.

This principle of independent assortment is also seen in eukaryotic cells during meiosis.

Mendel proposed this principle because during cell formation of the offspring, each individual Gene from the parents will first separate to stand on its own before cross linking up together, which made the offspring look different from the parents. The principle of independent assortment does not criticize gene linkage, it only highlight how gene in the garments of the parents forms offspring, by sperating to assort independently.

4 0
4 years ago
A compound containing sodium, chlorine, and oxygen is 25.42% sodium by mass. A 3.25 g sample gives 4.33×1022 atoms of oxygen. Wh
Tcecarenko [31]
step  one 
calculate  the  %  of  oxygen
from  avogadro  constant
1moles =  6.02  x  10  ^23  atoms
what  about    4.33  x10^22  atoms
= ( 4.33  x  10^ 22 x 1 mole )  /  6.02  10^23=   0.0719 moles
mass=  0.0719  x16=  1.1504   g
% composition   is therefore= ( 1.1504/3.25)  x100 = 35.40%
 step  two
calculate the  %  composition  of  chrorine
100-  (25.42  +  35.40)=39.18%

step  3
calculate the  moles   of  each  element
that   is  
Na  =  25.42  /23=1.1052  moles
Cl=  39.18  /35.5=1.1037moles
O=  35.40/16=  2.2125   moles
step  4
find  the  mole  ratio  by  dividing  each  mole  by  1.1037  moles
that  is
Na  =  1.1052/1.1037=1.001
Cl= 1.1037/1.1037=  1
0=2.2125 = 2
therefore  the  empirical  formula= NaClO2
8 0
3 years ago
What is the total pressure of air in lungs of an individual with oxygen at 100. mmHg, nitrogen at 573 mmHg, carbon dioxide at 0.
ryzh [129]

Answer: The total pressure of air in lungs of an individual is 760.28 mm Hg

Explanation:

According to Dalton's law, the total pressure is the sum of individual pressures.

p_{total}=p_A+p_B+p_C...

Given : p_{total} =total pressure of gases = ?

p_{O_2} = partial pressure of oxygen = 100 mm Hg

p_{N_2} = partial pressure of nitrogen = 573 mm Hg

p_{CO_2} = partial pressure of Carbon dioxide = 0.053 atm = 40.28 mm Hg(1 atm = 760 mmHg)

p_{H_2O} = partial pressure of water vapor = 47 torr = 47 mm Hg  (1torr=1 mm Hg)

putting in the values we get:

p_{total}=(100+573+40.28+47)mmHg

p_{total}=760.28mmHg

Thus the total pressure of air in lungs of an individual is 760.28 mm Hg

5 0
3 years ago
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