Answer:
18 grams of water, will be produced from 4 g of H₂ and 16g of O₂
Explanation:
Reaction: 2H₂ + O₂ ⇒ 2H₂O
Moles = Mass / Molar mass
Molar mass H₂ = 2g/m
Molar mass O₂ = 32 g/m
4g /2g/m = 2moles
16g / 32 g/m = 0.5 moles
Ratio is 2:1
For 2 moles of hydrogen, I need 1 mol of oxygen; I have 2 moles of H₂, but I only have 0.5 of O₂, so the O₂ is the limiting reagent.
1 mol of O₂ produces 2 mol of water
0.5 moles of O₂ will produce, the double → 1 mol of water.
Molar mass of water is 18 g/m
1 mol . 18 g/m = 18 g
