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ollegr [7]
3 years ago
10

The position-time equation for a certain train is xf=2.8m+(8.1m/s)t+(2.9m/s^2)t^2.

Physics
1 answer:
mash [69]3 years ago
3 0
The formula without numbers is
xf = xi + vxi(t) +  \frac{1}{2} (a) {t}^{2}
do the initial velocity would be
8.1 m/s
and the acceleration would be
2.9 m/s^2
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