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3 years ago

The position-time equation for a certain train is xf=2.8m+(8.1m/s)t+(2.9m/s^2)t^2.

1 answer:

3 0

The formula without numbers is
$xf = xi + vxi(t) + \frac{1}{2} (a) {t}^{2}$
do the initial velocity would be
8.1 m/s
and the acceleration would be
2.9 m/s^2

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What type of friction occurs when you are trying to move an object, but the object isnt moving?

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the answer is static friction

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3 years ago

Vector A has a magnitude of 63 units and points west, while vector B has the same magnitude and points due south. Find the magni

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Given :

Vector A has a magnitude of 63 units and points west, while vector B has the same magnitude and points due south.

To Find :

The magnitude and direction of

a) A + B .

b) A - B.

Solution :

Let , direction in north is given by +j and east is given by +i .

So , $A=-63i$ and $B=63j$

Now , A + B is given by :

$A+B=-63i+63j$

$| A+B | = 63\sqrt{2}$

Direction of A+B is 45° north of west .

Also , for A-B :

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Direction of A-B is 45° south of west .

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2 years ago

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masya89 [10]

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3 years ago

You have a pulley 10.4 cm in diameter and with a mass of 2.3 kg. You get to wondering whether the pulley is uniform. That is, is

madreJ [45]

Answer:

Explanation:

Given

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mass of Pulley(m)=2.3 kg

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height(h)=1 m

time taken=0.64 s

$h=ut+frac{at^2}{2}$

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$\alpha =93.84 rad/s^2$

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$T=1.7\times (9.8-4.88)$

T=8.364 N

and Tension will provide Torque

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$8.364\times 5.2\times 10^{-2}=I\times 93.84$

$I=0.463\times 10^{-2} kg-m^2$

$I_{original}=\frac{mr^2}{2}=0.31\times 10^{-2}kg-m^2$

Thus mass is uniformly distributed or some more towards periphery of Pulley

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Nikolay [14]

That's the 'electrostatic' force.

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2 years ago

Read 2 more answers