Technician A is incorrect so that means Technician B is correct.
Answer:B
Explanation:
Given
For motor A
Characteristic life(r)=4100 hr
MTTF=4650 hrs
shape factor(B )=0.8
For motor B
Characteristic life(r)=336 hr
MTTF=300 hr
Shape Factor (B)=3
Reliability for 100 hours
![R_a=e^{-\left ( \frac{T-r}{n}\right )B}](https://tex.z-dn.net/?f=R_a%3De%5E%7B-%5Cleft%20%28%20%5Cfrac%7BT-r%7D%7Bn%7D%5Cright%20%29B%7D)
![R_a=e^{-\left ( \frac{4650-4100}{100}\right )0.8}](https://tex.z-dn.net/?f=R_a%3De%5E%7B-%5Cleft%20%28%20%5Cfrac%7B4650-4100%7D%7B100%7D%5Cright%20%290.8%7D)
![R_a=e^{-4.4}=0.01227](https://tex.z-dn.net/?f=R_a%3De%5E%7B-4.4%7D%3D0.01227)
For B
![R_b=e^{-\left ( \frac{300-336}{100}\right )3}](https://tex.z-dn.net/?f=R_b%3De%5E%7B-%5Cleft%20%28%20%5Cfrac%7B300-336%7D%7B100%7D%5Cright%20%293%7D)
![R_b=e^{1.08}=2.944](https://tex.z-dn.net/?f=R_b%3De%5E%7B1.08%7D%3D2.944)
B is better for 100 hours
(b)For 750 hours
![R_a=e^{-0.5866}=0.55621](https://tex.z-dn.net/?f=R_a%3De%5E%7B-0.5866%7D%3D0.55621)
![R_b=e^{0.144}=1.154](https://tex.z-dn.net/?f=R_b%3De%5E%7B0.144%7D%3D1.154)
So here B is more Reliable.
Answer:
Rate of Entropy =210.14 J/K-s
Explanation:
given data:
power delivered to input = 350 hp
power delivered to output = 250 hp
temperature of surface = 180°F
rate of entropy is given as
![Rate\ of\ entropy = \frac{Rate\ of \ heat\ released}{Temperature}](https://tex.z-dn.net/?f=Rate%5C%20%20of%5C%20entropy%20%20%3D%20%5Cfrac%7BRate%5C%20of%20%5C%20heat%5C%20%20released%7D%7BTemperature%7D)
T = 180°F = 82°C = 355 K
Rate of heat = (350 - 250) hp = 100 hp = 74600 W
Rate of Entropy![= \frac{74600}{355} = 210.14 J/K-s](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B74600%7D%7B355%7D%20%3D%20210.14%20J%2FK-s)
(a) The number of vacancies per cubic centimeter is 1.157 X 10²⁰
(b) ρ = n X (AM) / v X Nₐ
<u>Explanation:</u>
<u />
Given-
Lattice parameter of Li = 3.5089 X 10⁻⁸ cm
1 vacancy per 200 unit cells
Vacancy per cell = 1/200
(a)
Number of vacancies per cubic cm = ?
Vacancies/cm³ = vacancy per cell / (lattice parameter)³
Vacancies/cm³ = 1 / 200 X (3.5089 X 10⁻⁸cm)³
Vacancies/cm³ = 1.157 X 10²⁰
Therefore, the number of vacancies per cubic centimeter is 1.157 X 10²⁰
(b)
Density is represented by ρ
ρ = n X (AM) / v X Nₐ
where,
Nₐ = Avogadro number
AM = atomic mass
n = number of atoms
v = volume of unit cell
A safety device called a cotter pin. The cotter pin fits through a hole in the bolt or part. This keeps the nut from turning and possibly coming off.