Answer:
1) 63.66 ohm
2) 188.49 ohm
Explanation:
Data provided in the question:
Part 1
Capacitance, C = 5μF = 5 × 10⁻⁶ F
Frequency = 500 Hz
Now,
Impedance =
or
Impedance =
or
Impedance = 63.66 ohm
Part 2
Inductance = 60 mH = 60 × 10⁻³ H
Frequency = 500 Hz
Now,
Impedance for an inductor = 2πfL
thus,
Impedance = 2 × π × 500 × 60 × 10⁻³
= 188.49 ohm
Answer:
The number of germanium atoms per cubic centimeter for this germanium-silicon alloy is 3.16 x 10²¹ atoms/cm³.
Explanation:
Concentration of Ge () = 15%
Concentration of Si (C) = 85%
Density of Germanium (ρ) = 5.32 g/cm³
Density of Silicon (ρ) = 2.33 g/cm³
Atomic mass of Ge (A)= 72.64 g/mol
To calculate the number of Ge atoms per cubic centimeter for the alloy, we will use the formula:
No of Ge atoms/cm³=[Avogadro's Number*]/([
*A
/ρ
)+(C
*A
/ρ
)]
= (6.02x10²³ * 15%) / [(15% * 72.64/5.32)+(72.64*85%/2.33)]
= (9.03x10²²)/(2.048+26.499)
= (9.03x10²²)/(28.547)
No of Ge atoms/cm³ = 3.16 x 10²¹ atoms/cm³