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Tomtit [17]
2 years ago
12

A dog whistle is designed to produce a sound with a frequency beyond that which can be heard by humans (between 20 000 Hz and 27

000 Hz). If a particular whistle produces a sound with a frequency of 2.5 x 104 Hz, what is the sound's wavelength? Assume the speed of sound in air is 331 m/s.​
Physics
1 answer:
krek1111 [17]2 years ago
3 0

Answer:

Explanation:

331 m/s / 2.5e4 cyc/s = 0.01324 m ≈ 1.3 cm

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In a hydroelectric dam the potential energy of lake water is transformed into _ energy as it begins to more.
Marianna [84]

Answer:

mechanical energy

Explanation:

7 0
3 years ago
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A friction force of 280 N exists between a cart and the path. If the force of reaction is 766 N, what is the minimum action forc
MatroZZZ [7]

force of friction on the cart is given as

F_f = 280 N

here we also know the reaction force due to surface

R = 766 N

so we can say reaction force is given as

R = \sqrt{F_n^2 + F_f^2}

766 = \sqrt{F_n^2 + 280^2}

F_n^2 = 766^2 - 280^2

F_n = 713 N

now by force balance we will say

F_y + F_n = mg

F_y = mg - F_n

F_x = F_f

also we know that

F_f = \mu * F_n

280 = \mu * 713

\mu = 0.39

now minimum force required to set this into motion

F_{min} = \frac{\mu mg}{\sqrt{1 + \mu^2}}

here we know that

mg = F_n = 713 N

F_{min} = \frac{0.39* 713}{\sqrt{1 + 0.39^2}}

F_{min} = 259 N

So it will require 259 N minimum force to move it

3 0
3 years ago
Which best describes most covalent compounds?<br> O soft<br> O brittle<br> 3<br> O cold<br> O warm
LUCKY_DIMON [66]

Answer: Brittle

Explanation:

took the test and I chose Soft, Soft is the wrong answer don't choose it. The CORRECT ANSWER IS BRITTLE

7 0
3 years ago
Determine the stopping distances for a car with an initial speed of 88 km/h and human reaction time of 2.0 s for the following a
seropon [69]

Explanation:

Given that,

Initial speed of the car, u = 88 km/h = 24.44 m/s

Reaction time, t = 2 s

Distance covered during this time, d=24.44\times 2=48.88\ m

(a) Acceleration, a=-4\ m/s^2

We need to find the stopping distance, v = 0. It can be calculated using the third equation of motion as :

s=\dfrac{v^2-u^2}{2a}

s=\dfrac{-(24.44)^2}{2\times -4}

s = 74.66 meters

s = 74.66 + 48.88 = 123.54 meters

(b) Acceleration, a=-8\ m/s^2

s=\dfrac{v^2-u^2}{2a}

s=\dfrac{-(24.44)^2}{2\times -8}

s = 37.33 meters

s = 37.33 + 48.88 = 86.21 meters

Hence, this is the required solution.

4 0
3 years ago
After the box comes to rest at position x1, a person starts pushing the box, giving it a speed v1. when the box reaches position
KiRa [710]

As we know by work energy theorem

total work done = change in kinetic energy

so here we can say that wok done on the box will be equal to the change in kinetic energy of the system

W_p = KE_f - KE_i

initial the box is at rest at position x = x1

so initial kinetic energy will be ZERO

at final position x = x2 final kinetic energy is given as

KE_f = \frac{1}{2}mv_1^2

now work done is given as

W_p = \frac{1}{2}mv_1^2 - 0

so we can say

W_p = \frac{1}{2}mv_1^2

so above is the work done on the box to slide it from x1 to x2

3 0
3 years ago
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