Answer:
850 Calories.
Explanation:
The following data were obtained from the question:
Mass (M) = 50 g
Initial temperature (T1) = 20 °C
Final temperature (T2) = 37 °C
Specific heat capacity (C) of water = 1 cal/g°C
Heat absorbed (Q) =..?
Next, we shall determine the change in temperature of water.
This can be obtained as follow:
Initial temperature (T1) = 20 °C
Final temperature (T2) = 37 °C
Change in temperature (ΔT) =..?
Change in temperature (ΔT) = T2 – T1
Change in temperature (ΔT) = 37 – 20
Change in temperature (ΔT) = 17 °C
Finally, we shall determine the heat absorbed. This can be obtained as follow:
Mass (M) = 50 g
Specific heat capacity (C) of water = 1 cal/g°C.
Change in temperature (ΔT) = 17 °C
Heat absorbed (Q) =..?
Q = MCΔT
Q = 50 x 1 x 17
Q = 850 Calories
Therefore, the heat absorbed is 850 Calories.
Answer:
1.15 atm
Explanation:
According to Dalton's law of partial pressures, the total pressure is the sum of all the partial pressures of the gases present in the mixture.
Therefore we have:
Total pressure = partial pressure of carbon monoxide + partial pressure of oxygen + partial pressure of carbon dioxide
We were given the following:
Total pressure = 2.45 atm
Pressure of oxygen = 0.65 atm
Pressure of carbon monoxide = x
Pressure of carbon dioxide = 0.65 atm
Therefore:
2.45 = x + 0.65 + 0.65
2.45 = x + 1.3
x = 2.45 - 1.3
x = 1.15 atm
Answer:
- <em>The solution expected to contain the greatest number of solute particles is: </em><u>A) 1 L of 1.0 M NaCl</u>
Explanation:
The number of particles is calculated as:
a) <u>For Ionic compounds</u>:
- molarity × volume in liters × number of ions per unit formula.
b) <u>For covalent compounds</u>:
- molarity × volume in liters
The difference is a factor which is the number of particles resulting from the dissociation or ionization of one mole of the ionic compound.
So, calling M the molarity, you can write:
- # of particles = M × liters × factor
This table show the calculations for the four solutions from the list of choices:
Compound kind Particles in solution Molarity # of particles
(dissociation) (M) in 1 liter
A) NaCl ionic ions Na⁺ and Cl⁻ 1.0 1.0 × 1 × 2 = 2
B) NaCl ionic ions Na⁺ anc Cl⁻ 0.5 0.5 × 1 × 2 = 1
C) Glucose covalent molecules 0.5 0.5 × 1 × 1 = 0.5
D) Glucose covalent molecules 1.0 1.0 × 1 × 1 = 1
Therefore, the rank in increasing number of particles is for the list of solutions given is: C < B = D < A, which means that the solution expected to contain the greatest number of solute particles is the solution A) 1 L of 1.0 M NaCl.
