Answer:
Energy = 1.5032*10^(-10) Joules
Explanation:
By Einstein's relativistic energy equation, we know that the energy of a given particle is given by:
Energy = rest energy + kinetic energy.
= m*c^2 + (γ - 1)*mc^2
Where γ depends on the velocity of the particle.
But if the proton is at rest, then the kinetic energy is zero, and γ = 1
Then the energy is just given by:
Energy = m*c^2
Where we know that:
mass of a proton = 1.67*10^(-27) kg
speed of light = c = 2.9979*10^(8) m/s
Replacing these in the energy equation, we get:
Energy = ( 1.6726*10^(-27) kg)*( 2.9979*10^(8) m/s)^2
Energy = 1.5032*10^(-10) kg*m^2/s^2
Energy = 1.5032*10^(-10) J
I think the answer is the second one
The torque that will bring the balls to halt, t = 0.34 Nm
What is rotating?
In physics and mechanics, torque is the rotational equivalent of linear force. It is also referred to as the moment, moment of force, rotational force, or turning effect, depending on the field of study. It represents the capability of a force to produce a change in the rotational motion of the body.
Center of Mass of Rod = (1 * 0 + 2.0 * 1.1) /(1.0 + 2.0)
Center of Mass of Rod = 0.73 m
ω = 21 rpm
ω = 21 * (2*pi)/60 rad/s
ω = 2.2 rad/s
Time to bring Halt = 5.2 s
Angular De-acceleration = 2.2/5.2 rad/s^2
α = 0.423 rad/s^2
We know,
torque = (moment of inertia) * (angular acceleration)
t = I * α
Where
I = m1*r1^2 + m2*r2^2
I = 1kg * (0.73)^2 + 2kg * (1.1-0.73)^2
I = 0.8067 kg*m^2
Substituting Values -
torque = 0.8067 Kg*m^2 * 0.423 rad/s^2
torque = 0.34 N*m
The torque that will bring the balls to halt, t = 0.34 Nm
To learn more about the torque the link is given below:
brainly.com/question/18883167?
#SPJ4
Explanation:
= 46.67 N(cos 50°) = 30.0 N
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