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Assoli18 [71]
3 years ago
15

The diagram shows the top view of a 65-kg student at point A on an amusement park ride. The ride spins the student in a horizont

al circle with a radius of 2.5 m, at a constant speed of 8.6 m/s. The floor is lowered and the student remains against the wall without falling to the floor.
The magnitude of the centripetal force acting on the student at point A is approximately

Question 4 options:

1398 N

47 N

223 N

1923 N

Physics
1 answer:
Elza [17]3 years ago
3 0

Answer:

1923 N

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 65 Kg

Radius (r) = 2.5 m

Velocity (v) = 8.6 m/s

Centripetal force (F) =?

The centripetal force, F, can be obtained by using the following formula:

F = mv²/r

F = 65 × 8.6² / 2.5

F = 65 × 73.96 / 2.5

F = 4807.4 / 2.5

F = 1922.96 ≈ 1923 N

Thus, the magnitude of the centripetal's force acting on the student is approximately 1923 N

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What is the purpose of using significant figures? How does it relate to accuracy, precision, resolution, and uncertainty?
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Answer:

#see solution for details

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7 0
3 years ago
Find the length (in m) of an organ pipe closed at one end that produces a fundamental frequency of 494 Hz when air temperature i
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Answer:

0.173 m.

Explanation:

The fundamental frequency of a closed pipe is given as

fc = v/4l .................. Equation 1

Where fc = fundamental frequency of a closed pipe, v = speed of sound  l = length of the pipe.

Making l the subject of the equation,

l = v/4fc ................ Equation 2

also

v = 331.5×0.6T ................. Equation 3

Where T = temperature in °C, T = 18.0 °c

Substitute into equation 3

v = 331.5+0.6(18)

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Substitute into equation 2

l = 342.3/(4×494)

l = 342.3/1976

l =0.173 m.

Hence the length of the organ pipe = 0.173 m.

7 0
3 years ago
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