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3 years ago

why it is not possible to determine drift velocity of electron by timing its travel through conductor.

1 answer:

6 0

The main reason is that electrons are too small to see.

But even if you could see them, a better reason is the fact that
all electrons are identical. So if you spotted one electron on its
way into the conductor, and then start watching the other end to
see when your electron gets there, you would see trillions of trillions
of trillions of electrons pouring out over there, and you'd have no way
to tell which electron is the one you're waiting for.

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A 6-in-wide polyamide F-1 flat belt is used to connect a 2-in-diameter pulley to drive a larger pulley with an angular velocity

Likurg_2 [28]

Answer:

a) Fc = 4.15 N, Fi = 435.65 N, (F1)a = 640 N, and F2 = 239.6 N,

b) Ha = 1863.75 N, nfs = 1 , length = 11.8 mm

Explanation:

Given that:

γ= 9.5 kN/m³ = 9500N/m3

b = 6 inches = 0.1524 m

t = 0.0013 mm

d = 2 inches = 0.0508 m

n = 1750 rpm

$H_{nom}=2hp=1491.4W$

L = 9 ft = 2.7432 m

Ks = 1.25

g = 9.81 m/s²

$w=\gamma b t = 9500* 0.1524*0.0013=1.88N/m$

$V=\frac{\pi d n}{60} =\pi *0.0508*1750/60=4.65 m/s$

$F_c=\frac{wV^2}{g}=1.88*4.65^2/9.81=4.15N$

$(F_1)_a=bF_aC_pC_v=0.1524*6000*0.7*1=640N$

$T=\frac{H_{nom}n_dK_s}{2\pi n}= \frac{1491*1.25*1}{2*\pi*1750/60}=10.17Nm$

$F_2=(F_1)_a-\frac{2T}{D}= 640-\frac{2*10.17}{0.0508} =239.6N$

$F_i=\frac{(F_1)_a+F_2}{2} -F_c=435.65N$

$H_a=1491*1.25=1863.75W$

$n_f_s=\frac{H_a}{H_{nom}K_S }=1$

dip = $\frac{L^2w}{8F_i} =\frac{2.7432*1.88}{435.65}=11.8mm$

7 0

2 years ago

Consider two metallic rods mounted on insulated supports. One is neutral, the other positively charged. You bring the two rods c

EastWind [94]

Answer:

I think it will be half of the initial charge

Explanation:

Because we know, the resulting charge will be q1+q2/2, since one is neutral so the charge will be half q/2

3 0

3 years ago

Use the worked example above to help you solve this problem. A wire carries a current of 21.8 A from west to east. Assume that a

PSYCHO15rus [73]

Answer:

Themagnitude of the force is 0.0415N and is directed vertically upwards. The solution to this problem uses the relationship between the Force experienced by a conductor in a magnetic field, the current flowing through the conductor, the length of the conductor and the magnitude of the electric field vector.

Mathematically this can be expressed as

F = I × L ×B

Where F = Force in newtons N

I = current in ampres A

L = length of the conductor in meters (m)

B = magnetic field vector in T

Explanation:

The calculation can be found in the attachment below.

Thedirection of the force can be found by the application of the Fleming's right hand rule. Which states that hold out the right hand with the index finger pointing in the direction of the magnetic field and the thumb pointing in the direction of the current in the conductor, then the direction which the middle finger points is the direction of the force exerted on the conductor. By applying this the direction is vertically upwards.

4 0

3 years ago

What are some of the causes that disrupt the natural balance of the ecosystem?

dangina [55]

Overpopulation of predators

5 0

3 years ago

Read 2 more answers

1. What happens in terms of heat transfer the longer you sit near the fire?

MAVERICK [17]

Answer:

In a camping fire conduction serves to transfer heat through the ground from where the fire is located, spreading out in a gradual, spherical pattern. This often goes unnoticed by people who sit close to a fire, but as the ground warms, convection currents moving across it also transfer some of this heat from the solid surface to the air as well.

Explanation:

True dat

8 0

3 years ago