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3 years ago

What type of landform is depicted here? a. a mountain b. a depression c. a valley

Physics

1 answer:

Harrizon [31]3 years ago

6 0

Answer:

b.mountain the correct answer

Explanation:

what type of ladform ids depicted here? a.a b. mountain b. a depression c. avaley

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Find me the answer I will mark you as the brainlist

marysya [2.9K]

Answer:

Explanation:

1) J = P = 100 g

Mass does not change with location.

2) 10 m/s

v² = u² + 2as

0² = u² + 2(-10)(5)

3) N(ewton)

4 0

2 years ago

) A toy rocket is launched vertically from ground level (y = 0 m), at time t = 0.0 s. The rocket engine provides constant upward

Talja [164]

Answer:

The time interval during which the rocket engine provides upward acceleration is 2.1 s

Explanation:

The equations for the height of the rocket are as follows:

y = y0 + v0 · t + 1/2 · a · t²

and, after the engine burnout:

y = y0 + v0 · t + 1/2 · g · t²

Where:

y = height of the rocket at time t

y0 = initial height

v0 = initial velocity

t = time

a = upward acceleration

g = acceleration due to gravity (downward)

The velocity of the rockey is given by this equation:

v = v0 + a · t (v0 = 0 because the rocket is launched from rest)

v = a · t

and after burnout:

v = v0 + g · t

Where v = velocity at time t

We know that when the altitude is 64 m the velocity is 60 m/s. Then let´s use the following equation system:

y = y0 + v0 · t + 1/2 · a · t² (y0 and v0 = 0)

v = a · t

Then:

64 m = 1/2 · a · t²

60 m/s = a · t

a = 60 m/s / t

Replacing "a = 60m/s / t" in the equation of height:

64 m = 1/2 ·( 60m/s / t) · t²

64 m = 30 m/s · t

t = 64 m / 30 m/s

t = 2.1 s

Then, the time interval during which the rocket engine provides upward acceleration is 2.1 s

5 0

3 years ago

A microscope has an objective lens with a focal length of 14.0mm . A small object is placed 0.80mm beyond the focal point of the

Nikolay [14]

Answer:

A. 260 mm

B. - 18

C. 175

Explanation:

The expression for the lens equation is

$\frac{1}{f} = \frac{1}{u} + \frac{1}{v}$

$\frac{1}{14.0mm} = \frac{1}{14.80 mm} + \frac{1}{v}$

$\frac{1}{v} = \frac{1}{14.0} - \frac{1}{14.80}$

v = 259 mm

= 260 mm or 26 cm (to 2 s.f)

check the attached files for additional solution

3 0

3 years ago

b) Assume the rod is 0.60 m long and has a mass of 0.50 kg, and the clay blob has a mass of 0.20 kg and moves at an initial velo

SOVA2 [1]

Answer:

The correct answer is "6.96 rad/s".

Explanation:

The given values are:

Length,

L = 0.6 m

Mass,

m₁ = 0.5 kg

m₂ = 0.2 kg

Initial velocity,

V = 8 m/s

Now,

The final angular velocity will be:

⇒ $\omega =\frac{6m_1V}{(4m_1+3m_2)L}$

By substituting the values, we get

⇒ $=\frac{6\times 0.2\times 8}{(4\times 0.2+3\times 0.5)0.6}$

⇒ $=\frac{9.6}{1.38}$

⇒ $=6.96 \ rad/s$

4 0

3 years ago

Conduction is heat in solids and liquids by _______

elena55 [62]

The answer is gases.

hope this help

4 0

3 years ago

What type of landform is depicted here? a. a mountain b. a depression c. a valley​

What type of landform is depicted here? a. a mountain b. a depression c. a valley