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GaryK [48]
3 years ago
15

Jerry is conducting an experiment to test friction. His setup is shown below. If he wants to test the friction between different

types of materials, what should he change in the setup above? A. Replace the mass with a different size mass B. Replace the string with a different length string C. Replace the spring scale with a different kind of scale D. Replace the wooden block with a different kind of block

Physics
1 answer:
professor190 [17]3 years ago
3 0

Answer:

The correct option is D

Explanation:

This question is incomplete because of the absence of the setup which as been attached below. The setup shows/determines/tests the friction of wood (which is a block material), since Jerry wants to test the friction between different types of materials, he will have to replace the wooden block with another type of block material of choice so as to determine the friction of that also.

In order to have a comprehensive experiment, Jerry can use 4-5 different types of block material in the course of the experiment.

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While john is traveling along a straight interstate highway, he notices that the mile marker reads 244 km. John travels until he
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2 years ago
A turntable, with a mass of 1.5 kg and diameter of 20 cm, rotates at 70 rpm on frictionless bearings. Two 540 g blocks fall from
ivann1987 [24]

Answer:

The turntable's angular speed after the event is 28.687 revolutions per minute.

Explanation:

The system formed by the turntable and the two block are not under the effect of any external force, so we can apply the Principle of Conservation of Angular Momentum, which states that:

I_{T}\cdot \omega_{o} = (2\cdot r^{2}\cdot m +I_{T})\cdot \omega_{f} (1)

Where:

I_{T} - Moment of inertia of the turntable, in kilogram-square meters.

r - Distance of the block regarding the center of the turntable, in meters.

m - Mass of the object, in kilograms.

\omega_{o} - Initial angular speed of the turntable, in radians per second.

\omega_{f} - Final angular speed of the turntable-objects system, in radians per second.

In addition, the momentum of inertia of the turntable is determined by following formula:

I_{T} = \frac{1}{2}\cdot M\cdot r^{2} (2)

Where M is the mass of the turntable, in kilograms.

If we know that \omega_{o} \approx 7.330\,\frac{rad}{s}, M = 1.5\,kg, m = 0.54\,kg and r = 0.1\,m, then the angular speed of the turntable after the event is:

I_{T} = \frac{1}{2}\cdot M\cdot r^{2}

I_{T} = 7.5\times 10^{-3}\,kg\cdot m^{2}

I_{T}\cdot \omega_{o} = (2\cdot r^{2}\cdot m +I_{T})\cdot \omega_{f}

\omega_{f} = \frac{I_{T}\cdot \omega_{o}}{2\cdot r^{2}\cdot m +I_{T}}

\omega_{T} = 3.004\,\frac{rad}{s} (28.687\,\frac{rev}{min})

The turntable's angular speed after the event is 28.687 revolutions per minute.

3 0
2 years ago
How can you determine the type of radiation an atom emits as its nucleus decays
Pie
Gamma raidiation and beta and alpha particles
7 0
3 years ago
A single point charge q is located at the center of both an imaginary cube and an imaginary sphere. How does the electric flux t
saveliy_v [14]

Answer:

Explanation:

Electric flux is defined as the flow of electric field intensity through a given surface.

Mathematically:

\phi=E.A.cos\ \theta

where:

E = electric field

A = area

θ = angle between the area vector and the electric field

Electric flux through the surface of a sphere will be uniform throughout the surface area due to a charge at the center of the sphere. The distance of the surface from the center is always at a constant distance of radius of the sphere.

Electric flux through the surface of a cube will be varying as the surface area is at a varying distance from the center of the cube. The distance of the surface from the center is not at a uniform distance from the center of the cube and so the projection of solid angle changes.

7 0
3 years ago
An ideal gas is enclosed in a piston, and 1600 J of work is done on the gas. As this happens, the internal energy of the gas inc
Phantasy [73]

Answer:

- 1100 J heat flows out

Explanation:

dW = - 1600 J (as work is done on the gas)

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According to the first law of thermodynamics

dQ = dU + dW

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dQ = - 1100 J

As heat is negative so it flows out.

3 0
2 years ago
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