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Vladimir [108]
3 years ago
11

A well blended mixture that contains at least one solute and one solvent is a _____.

Physics
1 answer:
tensa zangetsu [6.8K]3 years ago
4 0
A solution, an example is salt and water. brainliest?
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A hockey puck has a coefficient of kinetic friction of μk = .35. If the puck feels a normal force (FN) of 5 N, what is the frict
alina1380 [7]

Answer:

The frictional force is  F_f =  1.75 \  N

Explanation:

From the question we are told that

     The coefficient of kinetic force is  μk = 0.35

     The normal force felt by the puck is  F_N  =  5 \  N

Generally the frictional force that acts on the puck is mathematically represented as

          F_f =  \mu_k  *  F_N

=>       F_f =  0.35  *  5

=>       F_f =  1.75 \  N

3 0
3 years ago
Juan was wearing a bright red shirt in a very dark room. What color did his shirt appear to the people with him in the room? A)
ikadub [295]
It would appear black.   

Hope I helped.  
8 0
3 years ago
Read 2 more answers
A 3.00-kg rifle fires a 0.00500-kg bullet at a speed of 300 m/s. Which force is greater in magnitude:(i) the force that the rifl
alekssr [168]

Answer:

C. both forces have the same magnitude

Explanation:

Here the action force is equal to the reaction force in accordance with the Newton's third law of motion.

Also when we apply the conservation of momentum so that the momentum bullet and the momentum of the gun are equal and according to the second law of motion by Newton, we have force equal to the rate of change in momentum.

We have the equation for momentum as:

p=m.v

Newton's second law is Mathematically given as:

F=\frac{dp}{dt}

Momentum is constant and the reaction time is equal, so the force exerted will also be equal.

7 0
3 years ago
What forces are acting when you try to crack<br> an egg in your palm(will give brainliest)
Aleks [24]

Answer:

Kinetic energy in your palm

4 0
3 years ago
What is the potential energy at the origin due to an electric field of 5 x 10^6 N/C located at x=43cm,y=28cm?
Fudgin [204]

Answer:

potential energy at origin is 2.57*10^{6} volt

Explanation:

given data:

electric field E = 5*10^{6} N/C

at x = 43 cm, y = 28 cm

distance btween E and origin

\Delta r = \sqrt{43^2 +28^2}

\Delta r = 51.313 cm

potential energy per unit charge \Delta V = - Edr

\Delta V = 5*10^6*51.313*10^{-2} J/C

\Delta V  =  2.57*10^{6} volt

potential energy at origin is 2.57*10^{6} volt

3 0
4 years ago
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