-2 times the electronic charge whic is 1.6 x 10^-19 Coulombs. That is, it is "tiny".
Answer:
A
The current through the solution is
B
The current is moving from B to A
Explanation:
From the question we are told that
The number of that move from A to B is
The time taken to move from A to B
Since the value of 1 charge is
The quantity of charge Q that flow from A to B is mathematically given as
The number of that move from A to B is
Since time taken to move from A to B is equal to time taken to move from B to A
The quantity of charge Q that flow from B to A is mathematically given as
The total quantity of charge is
The current flowing through the solution is
The flow is from B to A cause current flow from the positive terminal to negative terminal
Answer:
The focal length of the lens is 5.54 cm and the height of the image is -0.89 cm.
Explanation:
Given that,
Height of object h = 2 cm
Object distance u= -18 cm
Image distance v= 8 cm
We need to calculate the focal length of the lens
Using formula of lens
Where, f = focal length
Put the value into the formula
(II). We need to calculate the height of the image
Using formula of magnification
Put the value into the formula
Hence, The focal length of the lens is 5.54 cm and the height of the image is -0.89 cm.
ºC = K - 273
ºC = 600 - 273
T = 327ºC
Answer C
hope this helps!