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kompoz [17]
3 years ago
5

What is more dangerous, current or voltage? Why?

Chemistry
2 answers:
uysha [10]3 years ago
8 0

<em>Voltage </em><em>is </em><em>more </em><em>dangerous </em><em>because </em><em>current </em><em>is </em><em>just </em><em>a </em><em>phenomenon </em><em>that </em><em>happens </em><em>when </em><em>a </em><em>voltage </em><em>is </em><em>applied</em><em>. </em>

Dahasolnce [82]3 years ago
4 0
The higher the current, the more likely it is lethal. Since current is proportional to voltage when resistance is fixed (ohm's law), high voltage is an indirect risk for producing higher currents.
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The charges of a set of isoelectronic ions vary from 3+ to 3-. Place the ions in order of increasing size.
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3 years ago
An industrial chemist studying bleaching and sterilizing prepares several hypoclorite buffers.
Vanyuwa [196]

Answer:

pH is 7.60

Explanation:

Let's think the equations:

HClO + H₂O  ⇄  ClO⁻  +  H₃O⁺

As every weak acid, we make an equilbrium

The salt is dissociated in solution

NaClO → Na⁺  +  ClO⁻

                  HClO    +    H₂O    ⇄    ClO⁻    +     H₃O⁺

Initially       0.3m                            0.35m

We have the moles of acid, and the moles of conjugate base.

Reacts          x                                    X                  X

Some amount has reacted, so I obtained (in equilibrium) the moles of base + that amount, and the same amount for H₃O⁺ (ratio is 1:1)

HClO    +    H₂O    ⇄    ClO⁻    +     H₃O⁺

0.3 - x                        0.35 + x           x

Let's make the expression for Ka

Ka = [ClO⁻] . [H₃O⁺]  /  [HClO]

(we don't add water, because it is included in Ka)

2.9x10⁻⁸ = (0.35+x).x  / (0.3-x)

Ka is in order of 10⁻⁸, I can assume that 0.3-x is 0.3  and 0.35 +x =0.3

2.9x10⁻⁸ = (0.35)x  / (0.3)

(2.9x10⁻⁸ .  0.3) /0.35 = x

2.48x10⁻⁸ = x

This is [H₃O⁺]

For pH = - log [H₃O⁺]

pH = 7.60

3 0
3 years ago
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