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4 years ago

What is more dangerous, current or voltage? Why?

2 answers:

8 0

Voltage is more dangerous because current is just a phenomenon that happens when a voltage is applied. 

Dahasolnce [82]4 years ago

4 0

The higher the current, the more likely it is lethal. Since current is proportional to voltage when resistance is fixed (ohm's law), high voltage is an indirect risk for producing higher currents.

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What do you mean by commercial farming

Zinaida [17]

Answer

Commercial farming is a large-scale production of crops for sale, intended for widespread distribution to wholesalers or retail outlets.

5 0

3 years ago

A student burned 0.250 g of magnesium metal in an open crucible.Oxygen from the air combined with the metal forming magnesium ox

Varvara68 [4.7K]

Answer:

0.171 grams of oxygen combined with the metal.

Explanation:

$2Mg+O_2\rightarrow 2MgO$

Mass of magnesium oxide produced = 0.421 g

Mass of magnesium metal used = 0.250 g

Suppose reaction completely converts the magnesium into magnesium oxide.

Mass of oxygen combined with magnesium = m

0.421 g = 0.250 g + m

m = 0.421 g - 0.250 g = 0.171 g

0.171 grams of oxygen combined with the metal.

5 0

4 years ago

State whether each of the following is a molecular element molecular compound or ionic compound.

Goryan [66]

1.molecular element
2.ionic compound
3.molecular compound
4. molecular compound

5 0

3 years ago

Calculate the fractional saturation for hemoglobin when the partial pressure of oxygen is 40 mm Hg. Assume hemoglobin is 50%% sa

kumpel [21]

Answer:

The fractional saturation for hemoglobin is 0.86

Explanation:

The fractional saturation for hemoglobin can be calculated using the formula

$Y_{O_{2} } = \frac{(P_{O_{2} })^{h} } {(P_{50})^{h} + (P_{O_{2} })^{h} }$

Where $Y_{O_{2} } \\$ is the fractional oxygen saturation

${P_{O_{2} }$ is the partial pressure of oxygen

$P_{50}$ is the partial pressure when 50% hemoglobin is saturated with oxygen

and h is the Hill coefficient

From the question,

${P_{O_{2} }$ = 40 mm Hg

$P_{50}$ = 22 mm Hg

h = 3

Putting these values into the equation, we get

$Y_{O_{2} } = \frac{(P_{O_{2} })^{h} } {(P_{50})^{h} + (P_{O_{2} })^{h} }$

$Y_{O_{2} } = \frac{40^{3} }{22^{3} + 40^{3} }$

$Y_{O_{2} } = \frac{64000 }{10648 + 64000 }$

$Y_{O_{2} } = \frac{64000 }{74648 }$

$Y_{O_{2} } = 0.86$

Hence, the fractional saturation for hemoglobin is 0.86.

4 0

3 years ago

Which indicator would best distinguish between a solution with pH of 7.4 and a solution of 9.2?

I am Lyosha [343]

Answer: Big Chodes

Explanation: Big Choses make walter happy

3 0

4 years ago