If the object's <em>velocity is constant</em> ... (it's speed isn't changing AND it's moving in a straight line) ... then the net force on the object is zero.<em> (D)</em>
Either there are no forces at all acting on the object, OR there are forces on it but they're 'balanced' ... when you add up all of their sizes and directions, they just exactly cancel each other out, and they have the SAME EFFECT on the object as if there were no forces at all.
 
        
             
        
        
        
Answer:
<h2>
206.67N</h2>
Explanation:
The sum of force along both components x and y is expressed as;

The magnitude of the net force which is also known as the resultant will be expressed as 
To get the resultant, we need to get the sum of the forces along each components. But first lets get the acceleration along the components first.
Given the position of the object along the x-component to be x = 6t² − 4;


Similarly, 



Hence, the magnitude of the net force acting on this object at t = 2.15 s is approximately 206.67N
 
        
             
        
        
        
Hubble space telescope, Hubble deep field guide, moon, mercury, Saturn, sun, galaxy messier 101
 
        
                    
             
        
        
        
The match
you need to light the match before you can light anything else.
and after the match is lit, maybe light the oil lamp first
        
                    
             
        
        
        
Answer:
Therefore the ratio of diameter of the copper to that of the tungsten is 

Explanation:
Resistance: Resistance is defined to the ratio of voltage to the electricity.
The resistance of a wire is
- directly proportional to its length i.e 
- inversely proportional to its cross section area i.e 
Therefore 

ρ is the resistivity.
The unit of resistance is ohm (Ω).
The resistivity of copper(ρ₁) is 1.68×10⁻⁸ ohm-m
The resistivity of tungsten(ρ₂) is 5.6×10⁻⁸ ohm-m
For copper:


 ......(1)
......(1)
Again for tungsten:

 ........(2)
........(2)
Given that  and
   and    
Dividing the equation (1) and (2)

 [since
   [since  and
   and     ]
]



Therefore the ratio of diameter of the copper to that of the tungsten is 
