Answer:
The answer to your question is V2 = 29.6 l
Explanation:
Data
Pressure 1 = P1 = 12 atm
Volume 1 = V1 = 23 l
Temperature 1 = T1 = 200 °K
Pressure 2 = 14 atm
Volume 2 = V2 = =
Temperature 2 = T2 = 300°K
Process
1.- To solve this problem use the Combine gas law.
P1V1/T1 = P2V2/T2
-Solve for V2
V2 = P1V1T2 / T1P2
2.- Substitution
V2 = (12)(23)(300) / (200)(14)
3.- Simplification
V2 = 82800 / 2800
4.- Result
V2 = 29.6 l
Answer:
ΔG° = -5.4 kJ/mol
ΔG = 873.2 J/mol = 0.873 kJ /mol
Explanation:
Step 1: Data given
ΔG (NO2) = 51.84 kJ/mol
ΔG (N2O4) = 98.28 kJ/mol
Step 2:
ΔG = ΔG° + RT ln Q
⇒with Q = the reaction quatient
⇒with T = the temperature = 298 K
⇒with R = 8.314 J / mol*K
⇒with ΔG° = ΔG° (N2O4) - 2*ΔG°(NO2
)
⇒ ΔG° = 98.28 kJ/mol - 2* 51.84 kJ/mol
⇒ ΔG° = -5.4 kJ/mol
Part B
ΔG = ΔG° =RT ln Q
⇒with G° = -5.4 kj/mol = -5400 j/mol
⇒
with R = 8.314 J/K*mol
⇒with T = 298 K
⇒with Q = p(N2O4)/ [ p(NO2) ]² = 1.63/0.36² = 12.577
ΔG = -5400 + 8.314 * 298 * ln(12.577)
ΔG = -5400 + 8.314 * 298 * 2.532
ΔG = 873.2 J/mol = 0.873 kJ/mol
Answer:
a) equilibrium shifts towards the right
b) equilibrium shifts towards the right
c) equilibrium shifts towards the left
d) has no effect on equilibrium position
e) has no effect on equilibrium position
Explanation:
A reversible reaction may attain equilibrium in a closed system. A chemical system is said to be in a state of dynamic equilibrium when the rate of forward reaction is equal to the rate of reaction.
According to Le Chateliers principle, when a constraint such as a change in temperature, pressure, volume or concentration is imposed upon a system in equilibrium, the equilibrium position shifts in such a way as to annul the constraint.
When the concentration of reactants is increased, the equilibrium position is shifted towards the right hand side and more products are formed. For an endothermic reaction, the reverse reaction is favoured by a decrease in temperature. Increase in pressure has no effect on the system since there are equal volumes on both sides of the reaction equation. Similarly, the addition of a catalyst has no effect on the equilibrium position since it speeds up both the forward and reverse reactions to the same extent.
Answer:
1. molarity is = 0.1174
2. molarity is = 9.3
3. molarity is =0.009392
Explanation:
Q#1.
mass of sucrose is 14.07g
molar mass of sucrose is 342 3g/mol
so, 14.07x1/342.3 = 0.0411
now the volume is of water is 0.35
so, 0.0411/0.35 = 0.1174
Q#2.
concentration is 4.5
so, 4.5x1/1000= 0.0045
then, 0.0411/0.0045 = 9.13
Q#3.
M1M1=M2M2
molarity of the same sucrose is 0.1174
so, diluted in 40mL
and the volumetric flask is 500mL
so, 0.1174x40/500= 0.009392
