Answer: 565.245kJ
To answer this question, you need to know how much water heat capacity which was 4.187 kJ/kg K. First, we need to find the calorie absorbed by water. Since the sample is 1kg, the initial temperature is 21 ∘C and final temperature is 34.5 <span>∘C then the calculation would be:
Energy= (Final temp - initial temp) * heat capacity * mass
Energy = (34.5-21) </span>∘C * 4.187 * kJ/kg K * 1kg= 56.5245 kJ
The energy is made from 0.1 gram, then for 1 gram of energy it should be:
1 gram/ 0.1gram x 56.5245 kJ= 565.245kJ
Matter can be classified according to physical and chemical properties. Matter is anything that occupies space and has mass. The three states of matter are solid, liquid, and gas. Extensive properties depend on the amount of material and include mass and volume.
Answer:
= 374.90 kPa
Calculation:
As we know atm and kiloPascal are related to each other as,
1 atm = 101.325 kPa
So,
3.70 atm = X
Solving for X,
X = (3.70 atm × 101.325 kPa) ÷ 1 atm
X = 374.90 kPa
Answer: Lanthanide and actinide series
Explanation: The elements with partially or fully filled f orbitals belong to f block elements.
f block elements include lanthanides and actinides. They are called so the lanthanides contain the first element named as lanthanum and actinides contain first element named as actinium. They are also called as inner transition elements.
All of them have general electronic configuration:
, where n = 6-7
HERE IS THE COMPLETE QUESTION
what is the calculated value of the cell potential at 298 k for an electrochemical cell with the following reaction, when the Cl2 pressure is 1.31 atm, the cl- concentration is at 1.28M, and the Ni2+ concentration is 1.24M
Answer:
Explanation:
From the given question;
We can see that Nickel is oxidized and Chlorine is reduced. We also known that Oxidation occurs at the anode while reduction occurs at the cathode.
SO the Oxidation and the reduction reaction can be expressed as shown below.
Oxidation :
Reduction :
<u> </u>
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By applying Nernst Equation; we have :
where
n= 2 moles