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Sidana [21]
3 years ago
8

A few Critical Thinking questions/creativity on the topic 'Particles of matter are very small'

Chemistry
1 answer:
Nookie1986 [14]3 years ago
7 0

Answer:

Any substance which occupies space and has mass is known as matter. States of matter: Matter exist in three different states that are Solid, Liquid and Gas. Matter is made up of very small particles

Explanation:

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Chemist question, helppp pls
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1: it is +2

2: it is +6

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Water acts as a<br> solvent<br> solute<br> solution<br> mixture
Serhud [2]
Answer: universal Solvent

Explanation: water can dissolve many substances than any other solvent. Because of this, water is sometimes called a UNIVERSAL SOLVENT.
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In your own words, describe two conditions that are necessary for an eclipse to occur
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4 0
3 years ago
Name the following alkyne: CH3CH₂C = CCH₂CH₂CH3
liubo4ka [24]

The given alkyne is Option A 3-heptyne

<h3>What is an Alkyne ?</h3>

The hydrocarbon having at least one C-C triple bond is called an Alkyne.

It has the general formula of   \rm C_n H_{2n+2} .

In the question it is being mentioned that it is an alkyne so there will be a triple bond and not a double bond.

It has been asked in the question that

CH3CH₂C ≡  CCH₂CH₂CH3 is which alkyne from the given option.

The counting of the Carbon chain is done from the left side and the Triple bond is at the 3rd Carbon , so 3-heptyne .

To know more about Alkyne

brainly.com/question/23508203

#SPJ1

<h3 />

6 0
2 years ago
1 how many moles of sodium bicarbonate are needed to neutralize 0.9ml of sulphuric acid at stp​
Natali5045456 [20]

Answer:

8.0356 * 10^-5 moles of NaHCO3

Explanation:

Sulphuric acid = H2SO4

Sodium bicarbonate = NaHCO3

The reaction between both compounds is given by;

2NaHCO3(aq) + H2SO4(aq) → Na2SO4(aq) + 2CO2(g) + 2H2O(l)

In the reactin above;

2 mol of NaHCO3 neutralizes 1 mol of H2SO4

At stp, 1 mol occupies 22.4 L;

1 mol = 22.4 L = 22400 mL

x mol = 0.9 mL

x = 0.9 / 22400 = 4.0178 * 10^-5 moles of H2SO4

Since 2 mol = 1 mol from the equation;

x mol = 4.0178 * 10^-5

x mol = 2 * 4.0178 * 10^-5

x = 8.0356 * 10^-5 moles of NaHCO3

3 0
3 years ago
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