Answer:
120.575 kJ is the activation energy for the souring process.
Explanation:
The formula for an activation energy is given as:
where,
= rate constant at
=
= rate constant at
=
= activation energy for the reaction = ?
R = gas constant = 8.314 J/mole.K
= initial temperature =
= final temperature =
Now put all the given values in this formula, we get:l
120.575 kJ is the activation energy for the souring process.
Answer : The standard enthalpy change for the combustion of CO(g) is, -283 kJ/mol
Explanation :
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
The combustion of will be,
The intermediate balanced chemical reaction will be,
(1)
(2)
Now we are reversing reaction 1 and then adding both the equations, we get :
(1)
(2)
The expression for enthalpy change for the reaction will be,
Therefore, the standard enthalpy change for the combustion of CO(g) is, -283 kJ/mol