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Kamila [148]
3 years ago
8

The following mechanism has been proposed for the gas-phase reaction of chloroform (CHCl3) and chlorine:

Chemistry
1 answer:
shusha [124]3 years ago
3 0

Answer:

Overall reaction equation is:

Cl2(g) + CHCl3(g) --> HCl(g) + CCl4(g)

The intermediates are Cl(g), CCl3(g).

Rate law= ka^1/2 c

Explanation:

This reaction is a non elementary reaction. A non elementary reaction is one that does not take place in a single reactive encounter. In other words, the reaction is comprised of many steps.

The overall reaction equation is the sum of all the reaction steps after all intermediates have been cancelled out. The rate law is obtained from the slowest step in the reaction sequence.

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3 years ago
90 POINTSSSS!!!
Katarina [22]

Answer:

\large \boxed{\text{-2043.96 kJ/mol}}

Explanation:

Assume the reaction is the combustion of propane.

Word equation: propane plus oxygen produces carbon dioxide and water

Chemical eqn:    C₃H₈(g) +   O₂(g) ⟶   CO₂(g) +   H₂O(g)

Balanced eqn:    C₃H₈(g) + 5O₂(g) ⟶ 3CO₂(g) + 4H₂O(g)

(a) Table of enthalpies of formation of reactants and products

\begin{array}{cc}\textbf{Substance} & \textbf{$\Delta_{\text{f}}$H/(kJ/mol}) \\\text{C$_{3}$H$_{8}$(g)} & -103.85 \\\text{O}_{2}\text{(g)} & 0 \\\text{CO}_{2}\text{(g)} & -393.51 \\\text{H$_{2}$O(g)} & -241.82\\\end{array}

(b)Total enthalpies of reactants and products

\Delta_{\text{rxn}}H^{\circ} = \sum \left( \Delta_{\text{f}} H^{\circ} \text{products}\right) - \sum \left (\Delta_{\text{f}}H^{\circ} \text{reactants} \right)\\= \text{-2147.81 kJ/mol - (-103.85 kJ/mol)}\\=  \text{-2147.81 kJ/mol + 103.85 kJ/mol}\\= \textbf{-2043.96 kJ/mol}\\\text{The enthalpy change is $\large \boxed{\textbf{-2043.96 kJ/mol}}$}

ΔᵣH° is negative, so the reaction is exothermic.

5 0
3 years ago
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almond37 [142]
6.02*10^23 is Avagadro's number representing the number of molecules per mole of substance.
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Answer:

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Explanation:

This one makes the most sense out of the answers.

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